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3 years ago

How does the graph change between point A and point C?

Mathematics

2 answers:

Sloan [31]3 years ago

8 0

It increases and then remains constant

natali 33 [55]3 years ago

3 0

Answer:

The graph increases, then remains constant.

Step-by-step explanation:

It says it increases between point A and B. Then it says between point B and C it is constant

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(6-7)[4-6]^2+2(-4)-2]

horsena [70]

This answer would be (-14).

6 0

3 years ago

If x = a + 2b, y=2a – b, and z=.–2b , what is x – y + 2z?

KiRa [710]

Answer:

-a-3b

Step-by-step explanation:

a+2b-2a-b+2(-2b)

-a+b-4b

-a-3b

-(a+3b)

7 0

3 years ago

A can of tuna has a volume 18pi cm3 and a height of 2 cm. Find the area of the label that wraps around the entire can and does n

Sphinxa [80]

Answer:

The area of the label is $12\pi\ cm^{2}$

Step-by-step explanation:

step 1

Find the radius

we know that

The volume of the cylinder (can of tuna) is equal to

$V=\pi r^{2} h$

In this problem we have

$V=18\pi\ cm^{3}$

$h=2\ cm$

substitute and solve for r

$18\pi=\pi r^{2} (2)$

Simplify

$18=r^{2}(2)$

$r^{2}=9$

$r=3\ cm$

step 2

<em>Find the lateral area of the can</em>

The lateral area of the cylinder (can of tuna) is equal to

$LA=2\pi rh$

we have

$r=3\ cm$

$h=2\ cm$

$LA=2\pi (3)(2)=12\pi\ cm^{2}$

5 0

3 years ago

A teacher was interested in knowing the amount of physical activity that his students were engaged in daily. He randomly sampled

klasskru [66]

Answer:

The standard error of the mean is 4.5.

Step-by-step explanation:

As we don't know the standard deviation of the population, we can estimate the standard error of the mean from the standard deviation of the sample as:

$\sigma_{\bar{x}}\approx\frac{s}{\sqrt{n}}$

The sample is [30mins, 40 mins, 60 mins, 80 mins, 20 mins, 85 mins]. The size of the sample is n=6.

The mean of the sample is:

$\bar{x}=\frac{1}n} \sum x_i =\frac{30+40+60+80+20+85}{6}=52.5$

The standard deviation of the sample is calculated as:

$s=\sqrt{\frac{1}{n-1}\sum (x_i-\bar x)^2} \\\\ s=\sqrt{\frac{1}{5}\cdot ((30-52.5)^2+(40-52.5)^2+(60-52.5)^2+(80-52.5)^2+(20-52.5)^2+(85-52.5)^2}\\\\s=\sqrt{\frac{1}{5} *3587.5}=\sqrt{717.5}=26.8$

Then, we can calculate the standard error of the mean as:

$\sigma_{\bar{x}}\approx\frac{s}{\sqrt{n}}=\frac{26.8}{6}= 4.5$

6 0

3 years ago

Which of the following fractions is equivalent to 4/20? 2/6 8/16 1/2 3/6 5/10 7/11

scZoUnD [109]

Answer:

1/2

Step-by-step explanation:

8 0

3 years ago