Question

I need help with this please

Answer 1

Answer:

steps below

Step-by-step explanation:

3.2.1   AD = DB* sin 2 = DB * sin θ   .. DE // AB   ∠2= θ  ... (1)

By laws of sines:  DB / sin ∠5 = x / sin ∠4    

∠4 = θ-α     ∠5 = 180°-∠1-∠4 = 180°-∠3-∠4 = 180°-(90°-θ)-(θ-α)) = 90°+α

DB = (x*sin ∠5)/sin (θ-α)

     = (x* sin (90°+α)) / sin (θ-α)

AD = DB*sinθ

     = (x* sin (90°+α))*sinθ / sin (θ-α)

     = x* (sin90°cosα+cos90°sinα)*sinθ / sin (θ-α)    .... sin90°=1, cos90°=0

     = x* cosα* sinθ / sin (θ-α)

3.2.2 Please apply Laws of sines to calculate the length