Answer:
x = √47
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Trigonometry</u>
- [Right Triangles Only] Pythagorean Theorem: a² + b² = c²
Step-by-step explanation:
<u>Step 1: Define</u>
We have a right triangle. We can use PT to solve for the missing side length.
<u>Step 2: Identify Variables</u>
Leg <em>a</em> = 5
Leg <em>b </em>= <em>x</em>
Hypotenuse <em>c</em> = √72
<u>Step 3: Solve for </u><em><u>x</u></em>
- Substitute [PT]: 5² + x² = (√72)²
- Exponents: 25 + x² = 72
- Isolate <em>x</em> term: x² = 47
- Isolate <em>x</em>: x = √47
Answer:
4x + 1
Step-by-step explanation:
note that (f + g)(x) = f(x) + g(x) , thus
f(x) + g(x)
= x + 3x + 1 ← collect like terms
= 4x + 1
It’s D, 10.7
8 - (4.7 x (-1)) - 2 = 10.7
The abscissa of the ordered pair, that is the x-coordinate, is equal to 1 and the ordinate, the y-coordinate, is equal to -1. In the cartesian plane, this point lies in the fourth (IV) quadrant. The standard position of the angle is that which has one of its side is in the x-axis.
Solve for the hypotenuse of the right triangle formed.
h = sqrt((-1)² + (1)²) = √2
Below items show the calculation for each of the trigonometric functions.
sin θ = opposite/hypotenuse = y/h = (-1)/(√2) = -√2/2
cos θ = adjacent/hypotenuse = x/h = (1)/√2 = √2/2
tan θ = opposite/adjacent = y/x = -1/1 = -1
