1 + tan ² Ф=sec²Ф
1+(12/5)²=sec²Ф
169/25=sec² Ф
sec Ф=⁺₋√(169/25)=⁺₋13/5
sec Ф=1/cos Ф ⇒cosФ=1/sec Ф
cos Ф>0 ⇔ sec Ф>0 ⇔ sec Ф=+ 13/5
cos Ф=1/secФ
cos Ф=1 / 13/5=5/13
we can calculate the sin Ф, with this method.
sin²Ф + cos²Ф=1 ⇒ sin Ф=⁺₋√(1-cos² Ф)
sin Ф=⁺₋√[1-(5/13)²]=⁺₋12/13
like cos Ф>0 and tan Ф>0 ⇒ sin Ф>0 ⇒sin Ф=12/13
answer: d.12/13
other method
tan Ф=sin Ф / cos Ф
12/5=sin Ф / 5/13
sin Ф=(12/5)*(5/13)=12/13
answer: d.12/13
X/2 is the same thing as 1/2x
Answer:
The amount of sale is approximately 5714.
Step-by-step explanation:
Let x be the sales made that will result to the same salary and let y be the same weekly salary.
We can represent both salaries as follows:
300 + 0.04x = y
100 + 0.075x = y
Subtracting the second equation from the first, we have:
200 – 0.035x = 0
0.035x= 200
x = 200/0.035
x ≈ 5714.
Therefore, the amount of sale is approximately 5714.
Answer:
B. 2x2y(x – 3y)(x + 3y)
Step-by-step explanation:
It is given in the question that
A rectangular box has a square base with an edge length of x cm and a height of h cm. The volume of the box is given by
And the edge length of the base is 12 cm, the edge length of the base is decreasing at a rate of 2 cm/min, the height of the box is 6 cm, and the height is increasing at a rate of 1 cm/min.
Here we differentiate V with respect to t, and we use product rule, that is
Substituting the given values , we will get
![[tex]dV/dt = 2(12)(6)(-2)+ 12^2(1)](https://tex.z-dn.net/?f=%5Btex%5DdV%2Fdt%20%3D%202%2812%29%286%29%28-2%29%2B%2012%5E2%281%29)
[/tex]
So at that moment, the volume is decreasing at the rate of
