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Lerok [7]
2 years ago
6

A national study, that revealed a normal distribution, revealed that the average time a student spends studying statistics on a

weekend is 60 minutes. A random sample of 11 students in BU 203 were asked to record their statistic study time over a weekend. The sample revealed an average study time of 44.27 minutes with a standard deviation of 20.4. With an alpha of 5% State the null hypothesis (H0) and the alternate hypothesis (H1). Draw the distribution.
Mathematics
1 answer:
Neporo4naja [7]2 years ago
5 0

Answer:

Null hypothesis = H0 : μ = 60

Alternative hypothesis = H1 : μ < 60

Step-by-step explanation:

From the question given :

μ = 60 minutes

xbar = 44.27 minutes

s = 20.4 minutes

The alternative hypothesis is the claim ; which is to hypothesize that the average studying time is 44.27 (which is less than the population average studying time)

The null hypothesis is the initial truth and it is the opposite of the alternative hypothesis.

The hypothesis are :

H0 : μ = 60

H1 : μ < 60

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Maru [420]

Answer:

The solution is

\boxed{x=6,y=-2}

Step-by-step explanation:


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\text{Hello there!}\\\\\text{To find your average, you would add all of the numbers together, then}\\\text{divide by how many there are}\\\\\text{The times are: 1.23, 1.04, and 1.18}\\\\\text{Add them together and divide by 3}\\\\1.23+1.04+1.18=3.45\\\\3.45\div3=1.15\\\\\boxed{\text{Average time: 1.15 minutes}}

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