Write an equation of the line that passes through (2,−5) and is parallel to the line 2y=3x+10
1 answer:
Step-by-step explanation:
Divide two on both sides to get rid of it and the make the equation in the form y = mx + c
y = 3/2x + 5
since both lines are parallel they must have the same gradient which is 3/2
y = 3/2x + c
All you have to do now is to replace x and y with (2, -5) to find c
x = 2
y = -5
-5 = 3/2 × 2 + c
-5 = 3 + c
c = -5-3
c = -8
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