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marin [14]
3 years ago
14

Write an equation of the line that passes through (2,−5) and is parallel to the line 2y=3x+10

Mathematics
1 answer:
LenaWriter [7]3 years ago
8 0

Step-by-step explanation:

Divide two on both sides to get rid of it and the make the equation in the form y = mx + c

\frac{2}{2} y = \frac{3}{2} x +  \frac{10}{2}

y = 3/2x + 5

since both lines are parallel they must have the same gradient which is 3/2

y = 3/2x + c

All you have to do now is to replace x and y with (2, -5) to find c

x = 2

y = -5

-5 = 3/2 × 2 + c

-5 = 3 + c

c = -5-3

c = -8

y  = \frac{3}{2} x  - 8

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F(x){3/4x+2 If x≠2<br> {-4. If x=2 <br> Whats f(-5), f(2),f(4)
satela [25.4K]

The values of the functions are -1/ 4, 3/ 16 and 3/ 8 respectively.

<h3>What is a function?</h3>

A function is a rule or expression showing the relationship between a dependent and independent variable.

We have the function to be;

f(x) = 3/ 4(x + 2)

Let's find f(-5), substitute the value of x as -5

f(-5) = 3/ 4 ( -5 + 2)

f(-5) = 3/ 4 × -3

f(-5)  = -1/ 4

f(2), substitute the value of x as  2

f(2) = 3/ 4(2 + 2)

f(2) = 3/ 4 (4)

f(2) = 3/ 16

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f(4) = 3/ 4(6)

f(4)  = 3/ 8

Thus, the values of the functions are -1/ 4, 3/ 16 and 3/ 8 respectively.

Learn more about functions here:

brainly.com/question/4025726

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2 years ago
For what value of x is the function g(x)=x/1-x NOT defined?
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If the value of y or f(x) is considered, you'll see that it is never possible to attain f(x)=0. In other terms (x,y)= (0,0) is not a defined point in the graph of the function because the graph doesnt pass through that point.

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