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marin [14]
2 years ago
14

Write an equation of the line that passes through (2,−5) and is parallel to the line 2y=3x+10

Mathematics
1 answer:
LenaWriter [7]2 years ago
8 0

Step-by-step explanation:

Divide two on both sides to get rid of it and the make the equation in the form y = mx + c

\frac{2}{2} y = \frac{3}{2} x +  \frac{10}{2}

y = 3/2x + 5

since both lines are parallel they must have the same gradient which is 3/2

y = 3/2x + c

All you have to do now is to replace x and y with (2, -5) to find c

x = 2

y = -5

-5 = 3/2 × 2 + c

-5 = 3 + c

c = -5-3

c = -8

y  = \frac{3}{2} x  - 8

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Step-by-step explanation:

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