Write an equation of the line that passes through (2,−5) and is parallel to the line 2y=3x+10
1 answer:
Step-by-step explanation:
Divide two on both sides to get rid of it and the make the equation in the form y = mx + c
y = 3/2x + 5
since both lines are parallel they must have the same gradient which is 3/2
y = 3/2x + c
All you have to do now is to replace x and y with (2, -5) to find c
x = 2
y = -5
-5 = 3/2 × 2 + c
-5 = 3 + c
c = -5-3
c = -8
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Answer:
f(-1) = -10
f(0) = -6
f(2) = 8
Step-by-step explanation:
As the function says, when x is below 0, the part that we have to use is 7x-3, and when is equal or greater we use 7x-6.
We do so and just replace de values of x in each equation.
Answer:
Probability that the wait time is greater than 37 minutes is 0.3474.
Step-by-step explanation:
We are given that the random variable X is known to be exponentially distributed and X be the waiting time for a car to pass by on a country road, where X has an average value of 35 minutes.
<u><em>Let X = waiting time for a car to pass by on a country road</em></u>
The probability distribution function of exponential distribution is given by;
where,
= parameter of distribution.
Now, the mean of exponential distribution is = which is given to us as 35 minutes that means
.
So, X ~ Exp( )
Also, we know that Cumulative distribution function (CDF) of Exponential distribution is given as;
, x > 0
Now, Probability that the wait time is greater than 37 minutes is given by = P(X > 37 min) = 1 - P(X 37 min)
P(X 37 min) =
{Using CDF}
= 1 - 0.3474 = 0.6525
So, P(X > 37 min) = 1 - 0.6525 = 0.3474
Therefore, probability that the wait time is greater than 37 minutes is 0.3474.