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Brums [2.3K]
2 years ago
15

If alpha and beta are zeroes of polynomial fx = 4x2-5x-1. Pls answer full questiob

Mathematics
1 answer:
Ede4ka [16]2 years ago
6 0
<h3>...................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................</h3><h2>I like 15 yr old girls.</h2>

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For me cross multiplying works really well.
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Use a protractor to find the measure of the largest angle in the figure. Write it in degrees.
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5 0
3 years ago
Daniella is interviewing for a job. She wants her take-home pay to be at least $51,000 
Lilit [14]
Okay. So Daniella wants to have a take-home pay of at least $51,000, but she ahs to pay 15% income tax, which means 15% of what she earns will be gone. To find out the least amont of salary she needs to make, we can write and solve a proportion. Set it up like this:

51,000/x = 85/100

This is because we are looking for the amount of money made overall, but the $51,000 is only part of the salary earned, and even though you pay 15% income tax, you still take home 85% of your salary. Cross multiply the valyes in order to get 5,100,000 = 85x. Divide each side by 85 to isolate the variable. 5,100,000/85 is 60,000. Let's check this by multiplying by 85% (0.85). 60,000 * 0.85 is 51,000. There. x = 60,000. Daniella will need to make at least $60,000.
5 0
3 years ago
A rectangular field is 90 yards long and 60 yards wide.Give the length and width of another rectangular field that has the same
Ilya [14]

Answer:

The length and width of another rectangular field with same perimeter but a larger area is 80 m by 70 m

Step-by-step explanation:

The perimeter of the existing field is

2(l + b)

= 2(90 + 60) = 2(150) = 300 yards

So we want another field having the same perimeter but a larger area

The area we have here is 90 * 60 = 5,400 square yards

If we had 80 by 70

Perimeter will still be 2(70 + 80) = 150

But the area will be 80 * 70 = 5,600 square yards

3 0
3 years ago
Find f(-3) for f(x) = 4(2)^x<br> A. 1/8<br> B. -32<br> C. 1/2<br> D. -24
Law Incorporation [45]

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Find f(-3) for f(x) = 4(2)^x

  • D.-24

((−3)(4))(2)

=(−12)(2)

=−24

8 0
3 years ago
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