Answer:
x = 4, TU = 22
Step-by-step explanation:
Given that TS bisects TU at Q , then
TQ = QU , substitute values
5x - 9 = 15 - x ( add x to both sides )
6x - 9 = 15 ( add 9 to both sides )
6x = 24 ( divide both sides by 6 )
x = 4
Thus
TU = 5x - 9 + 15 - x = 4x + 6 = 4(4) + 6 = 16 + 6 = 22
Answer:
yes
Step-by-step explanation:
A rational number is in the form p/q where p and q are both integers and the denominator q is not equal to zero. This means that the set of all real numbers are rational numbers.
Since q can be any integer apart from zero, it means that all integers are rational numbers i.e for q = 1.
Hence 2 which can be written as fraction as 2/1 is a rational number since the denominator (q = 1) is a non zero number
Find the x and y-intercepts of the equation. Then calculate the points at constant intervals and plot and connect those points on a makeshift graph. A quadratic equation can have 2 solutions, 1 solution, or none. The corresponding graphs(if two solutions) would most probably cross over the x-axis twice.
Hope this helps.
This is going to be 4 remainders one.
