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jonny [76]
3 years ago
5

Can you please give me the answer

Mathematics
2 answers:
ladessa [460]3 years ago
7 0

Answer:

Your answer should be B.  x + -1 +- √17

Step-by-step explanation:

Artemon [7]3 years ago
3 0

Answer:

B

Step-by-step explanation:

Given

x² + 2x + 1 = 17

Note that the quadratic on the left side is a perfect square, that is

(x + 1)² = 17 ( take the square root of both sides )

x + 1 = ± \sqrt{17} ( subtract 1 from both sides )

x = - 1 ± \sqrt{17} → B

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2√5(√3+3√5) (1.73+3+2.23)= (6.96) 2√5= 4.23 4.23(6.96)= 29.44
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The price of a sweater was slashed from $ 960 to $ 816 , which means the sweater was marked down $144, by a shopkeeper in the wi
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15% or 16%. Hope this helps! =)
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The equation of a line with a slope of 2 and passing through the point (-5,3) written in slope point form
joja [24]

y=ax+b

a=2

3=2*(-5)+b

thenb=13

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4 0
3 years ago
Read 2 more answers
Solve the equation (0°≤A≤360°)<br>a) √3sinA-cosA=√2​
Blizzard [7]

Step-by-step explanation:

√3sinA-cosA=√2

dividing both side by (√3²-1²=2 we get)

√3/2 sinA-1/2.cos A=√2/2

cos 30sinA-sin30cosA=√2/(√2×√2)

sinAcos30-cosAsin30=1/√2

sin(A-30)=sin45,sin(180-45)

therefore

A-30=45,135

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6 0
3 years ago
Q4: Write the equation in slope-intercept form of the line that is perpendicular to
forsale [732]

Answer:

5y  = x + 11

Step-by-step explanation:

Given parameters:

  Equation of the line ;

           y  = -5x + 1

  Coordinates = (2, -1)

Find the equation of a line perpendicular;

Solution:

A line perpendicular to  y  = -5x + 1  will have slope that is a negative inverse of the given one.

Equation of a straight line is expressed as;

           y  = mx + c

y and x are the coordinates

m is the slope

c is the y-intercept

        So, the slope of the new line perpendicular is \frac{1}{5} ;

Now let us find the y-intercept of the new line;

   x = -1 and y = 2

      2  = \frac{1}{5} x (-1) + c

           c  = 2 + \frac{1}{5}   = \frac{11}{5}  

The equation of the new line is;

          y  =  \frac{1}{5}x +  \frac{11}{5}  

or multiply through by 5;

        5y  = x + 11

5 0
3 years ago
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