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Pavel [41]
3 years ago
15

For his phone service, Ivan pays a monthly fee of $14, and he pays an additional $0.05 per minute of use. The least he has been

charged in a month is $74.75.What are the possible numbers of minutes he has used his phone in a month?
Mathematics
1 answer:
Tomtit [17]3 years ago
8 0

Answer:

1215 minutes are the possible numbers he has used his phone in a month.

Step-by-step explanation:

He has a monthly fee of 14$ then to the least that he has been charged we need to substract the monthly fee as follows:

Monthly charged = 74,75-14

Monthly charged= 60,75$

Then he pays an additional 0,05 $/minute of use, to know the consume:

Minutes= \frac{60,75}{0,05}

Minutes= 1215 possible numbers of minutes he has used his phone.

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Hey can someone plz help me with this??? *cute eyes*
Leto [7]

Answer:

A. 5

B. -5, 5

C. 5, 5

Step-by-step explanation:

A. |-6+(-1)| = 5

B. -6-(-1)=-6+1=-5

-1-(-6)=-1+6=5

C. |-6-(-1)|=|-6+1|=5

|-1-(-6)|=|-1+6|=5

5 0
3 years ago
Find the slope<br> (-5,2) (-12,-11)
KonstantinChe [14]

Answer:

m= 13/7

Step-by-step explanation:

(-5, 2) , (-12, -11)

Slope(m)

m= (y2-y1)/(x2-x1)

m= (-11 - 2)/(-12 + 5)

m= (-13)/(-7)

m= 13/7

5 0
3 years ago
he owner of a local supermarket wants to estimate the difference between the average number of gallons of milk sold per day on w
stellarik [79]

Answer:

90% confidence interval is ( -149.114, -62.666   )

Step-by-step explanation:

Given the data in the question;

Sample 1                                Sample 2

x"₁ = 259.23                            x"₂ = 365.12

s₁  = 34.713                              s₂ = 48.297

n₁ = 5                                       n₂ = 10

With 90% confidence interval for μ₁ - μ₂ { using equal variance assumption }

significance level ∝ = 1 - 90% = 1 - 0.90 = 0.1

Since we are to assume that variance are equal and they are know, we will use pooled variance;

Degree of freedom DF = n₁ + n₂ - 2 = 5 + 10 - 2 = 13

Now, pooled estimate of variance will be;

S_p^2 = [ ( n₁ - 1 )s₁² + ( n₂ - 1)s₂² ] / [ ( n₁ - 1 ) + ( n₂ - 1 ) ]

we substitute

S_p^2 = [ ( 5 - 1 )(34.713)² + ( 10 - 1)(48.297)² ] / [ ( 5 - 1 ) + ( 10 - 1 ) ]

S_p^2 = [ ( 4 × 1204.9923) + ( 9 × 2332.6 ) ] / [  4 + 9 ]

S_p^2 = [ 4819.9692 + 20993.4 ] / [  13 ]

S_p^2 = 25813.3692 / 13

S_p^2 = 1985.64378

Now the Standard Error will be;

S_{x1-x2 = √[ ( S_p^2 / n₁ ) + ( S_p^2 / n₂ ) ]

we substitute

S_{x1-x2 = √[ ( 1985.64378 / 5 ) + ( 1985.64378 / 10 ) ]

S_{x1-x2 = √[ 397.128756 + 198.564378 ]

S_{x1-x2 = √595.693134

S_{x1-x2 = 24.4068

Critical Value = t_{\frac{\alpha }{2}, df = t_{0.05, df=13 = 1.771  { t-table }

So,

Margin of Error E =  t_{\frac{\alpha }{2}, df × [ ( S_p^2 / n₁ ) + ( S_p^2 / n₂ ) ]

we substitute

Margin of Error E = 1.771 × 24.4068

Margin of Error E = 43.224

Point Estimate = x₁ - x₂ = 259.23 - 365.12 = -105.89

So, Limits of 90% CI will be; x₁ - x₂ ± E

Lower Limit = x₁ - x₂ - E = -105.89 - 43.224 = -149.114

Upper Limit = x₁ - x₂ - E = -105.89 + 43.224 = -62.666

Therefore, 90% confidence interval is ( -149.114, -62.666   )

3 0
3 years ago
12^x-2=20 solve for x
ioda
Your answer is x=1.243927
7 0
3 years ago
If x=-5 what is the value of x^2-1/x+1? A. 6 b. -4 c. 4 d. 5 4/5 e. 19 <br> need answers asap
xxTIMURxx [149]

Answer:

The answer is -6 but its not in the option

Step-by-step explanation:

\frac{ {x}^{2} - 1 }{ x  + 1}

Let x = -5

[(-5)²-1]/(-5+1)

= (25-1)/(-4)

= 24/-4

= -6

4 0
3 years ago
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