1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
avanturin [10]
3 years ago
5

The two-column proof below describes the statement and reason for proving that corresponding angles are congruent.

Mathematics
2 answers:
Shkiper50 [21]3 years ago
6 0

Second choice (B)

Hope this helps

noname [10]3 years ago
3 0
Step 6 wants us to show two angles which are also two interior angles that are located on the same side.

Interior angles are angles that are INSIDE the parallel lines.

On the diagram given, there are two pairs of interior angles that are on the same side:

Angle VQT and angle ZRS
Angle UQT and angle WRS

Two interior angles on the same sides add up to 180°

The missing statement that would fit statement in Step 6 is:
m∠VQT + m∠ZRS = 180°

Answer: Second option

You might be interested in
What is the opposite of 6/7
lorasvet [3.4K]
If you were to reverse it it would be 7/6, but if you need it in another form, tell me.
3 0
3 years ago
Read 2 more answers
Determine which of the ordered pairs are a part of the solution set of y + 3 < 2x (0, –4)
lorasvet [3.4K]

Answer:

(2,0) and (2,-2)

Step-by-step explanation:

y+3<2x

(2,0) is solution because 0+3<2*2, 3<4 and

(2,-2) because - 2+3<2*2, 1<4

5 0
4 years ago
Read 2 more answers
Х = 4<br> 3х — у = -1<br> How to solve ?
elena-s [515]
3+ - 1 I hole this helped
7 0
3 years ago
Answer please. Simplify the expression<br><br> 8y - 11y + 6
sattari [20]
8y - 11y + 6

Combine like terms

-3y + 6 is the simplified answer. 
5 0
3 years ago
A tank initially contains 60 gallons of brine, with 30 pounds of salt in solution. Pure water runs into the tank at 3 gallons pe
adoni [48]

Answer:

the amount of time until 23 pounds of salt remain in the tank is 0.088 minutes.

Step-by-step explanation:

The variation of the concentration of salt can be expressed as:

\frac{dC}{dt}=Ci*Qi-Co*Qo

being

C1: the concentration of salt in the inflow

Qi: the flow entering the tank

C2: the concentration leaving the tank (the same concentration that is in every part of the tank at that moment)

Qo: the flow going out of the tank.

With no salt in the inflow (C1=0), the equation can be reduced to

\frac{dC}{dt}=-Co*Qo

Rearranging the equation, it becomes

\frac{dC}{C}=-Qo*dt

Integrating both sides

\int\frac{dC}{C}=\int-Qo*dt\\ln(\abs{C})+x1=-Qo*t+x2\\ln(\abs{C})=-Qo*t+x\\C=exp^{-Qo*t+x}

It is known that the concentration at t=0 is 30 pounds in 60 gallons, so C(0) is 0.5 pounds/gallon.

C(0)=exp^{-Qo*0+x}=0.5\\exp^{x} =0.5\\x=ln(0.5)=-0.693\\

The final equation for the concentration of salt at any given time is

C=exp^{-3*t-0.693}

To answer how long it will be until there are 23 pounds of salt in the tank, we can use the last equation:

C=exp^{-3*t-0.693}\\(23/60)=exp^{-3*t-0.693}\\ln(23/60)=-3*t-0.693\\t=-\frac{ln(23/60)+0.693}{3}=-\frac{-0.959+0.693}{3}=  -\frac{-0.266}{3}=0.088

5 0
3 years ago
Other questions:
  • Given that x square + 5 x + c is a perfect square find the value of C ​
    8·1 answer
  • Round 672,831 to the nearest ten thousand
    10·1 answer
  • Solve 4^x+2 = 12 for x using the change of base formula log base b of y equals log y over log b.
    5·1 answer
  • Can someone show me how to do this?
    13·1 answer
  • What is the range of the function on the graph?
    7·2 answers
  • What is 896.854 in word form
    5·2 answers
  • The grocery store puts the apples into bags of 8 apples to sell. How many full bags of 8 apples can they make?
    11·2 answers
  • 4. Square ABCD is shown. What is the length of diagonal AC? Round to the nearest tenth, if necessary.
    14·1 answer
  • Compare. Select &lt;, &gt;, or=.<br> 6.61? 6.610<br> The awnser is 6.610
    10·1 answer
  • HURRY WILL MARK AS BRAINLIEST IF CORRECT
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!