2026.8378 I might get it wrong but I’m pretty sure it’s right
3Ca(NO₃)₂(aq) + 2Na₃PO₄(aq) → Ca₃(PO₄)₂(s) + 6NaNO₃(aq)
3Ca²⁺ + 6NO₃⁻ + 6Na⁺ + 2PO₄³⁻ → Ca₃(PO₄)₂ + 6Na⁺ + 6NO₃⁻
3Ca²⁺ + 2PO₄³⁻ → Ca₃(PO₄)₂ (calcium phosphate is the precipitate)
Answer:
Number of moles = 0.51 mol
Explanation:
Given data:
Mass of CO₂ = 22.4 g
Number of moles = ?
Solution:
Number of moles of CO₂:
Number of moles = mass/molar mass
Molar mass of CO₂ = 44 g/mol
by putting values,
Number of moles = 22.4 g/ 44 g/mol
Number of moles = 0.51 mol
