2 years ago

Question 5 of 5

Chemistry

1 answer:

Romashka [77]2 years ago

8 0

Answer:

Explanation:

l took the test

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Determine the expected diffraction angle for the first-order diffraction from the (111) set of planes for FCC nickel (Ni) when m

faust18 [17]

Answer:

56°

Explanation:

First calculate $a:$

$a=2 R \sqrt{2}=2(0.1246) \sqrt{2}=0.352 \mathrm{nm}$

The interplanar spacing can be calculated from:

$d_{111}=\frac{a}{\sqrt{1^{2}+1^{2}+1^{2}}}=\frac{0.352}{\sqrt{3}}=0.203 \mathrm{nm}$

The diffraction angle is determined from:

$\sin \theta=\frac{n \lambda}{2 d_{111}}=\frac{1(0.1927)}{2(0.2035)}=0.476$

Solve for $\theta$

$\theta=\sin ^{-1}(0.476)=28^{\circ}$

The diffraction angle is:

$2 \theta=2\left(28^{\circ}\right)=56^{\circ}$

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If you have 85g of sulfur dioxide at STP, how many moles do you have?

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Answer: 1.32

Explanation:

Given

85 gm of sulfur dioxide is present at STP

The molar mass of sulfur dioxide is $32+2\times 16=64\ g/mol$

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