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aivan3 [116]
2 years ago
6

Question 5 of 5

Chemistry
1 answer:
Romashka [77]2 years ago
8 0

Answer:

A

Explanation:

l took the test

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A saturated solution of copper (II) hydroxide is prepared in a beaker by adding the solid to water and stirring. When the soluti
12345 [234]

Answer:

addition of aqueous hydrochloric acid

Explanation:

The solubility of copper (ll) hydroxide in water is negligible. This implies that the substance is only slightly soluble in water.

However, the addition of aqueous hydrochloric acid leads to the following reaction;

Cu(OH)2 + 2HCl ---------> CuCl2 + 2H2O

Copper II chloride is soluble in water hence the crystals dissolve when stirred. and the molar solubility increases.

8 0
3 years ago
Compare and contrast the goals of the General Mining Law of 1872 and the proposed Hardrock Mining and Reclamation Act of 2009.
Ad libitum [116K]

Answer: seen below

Explanation:

the goals of the General Mining Law of 1872 state that, anyone can stake mining claims on federal land, and they pay no more than $5 an acre while they keep 100% of profits with little to no environmental provisions.

Taxpayers pay for clean up of sites.

While the goals of proposed Hardrock Mining and Reclamation Act of 2009 includes, Increasing acreage of lands off limits to exploration and development. Protecting of National Parks and National Monuments is essential. Giving land managers the ability to balance mineral activities with other uses of public land. Giving state, local and tribal government the ability to put lands off limits to mining although, this bill never became law.

4 0
3 years ago
s sample of thorium-234 has a half life of 25 days. will all the thorium undergo radioactive decay in 50 days?
Assoli18 [71]

Answer:

25% thorium will left after 50 days.

Explanation:

Half life:

A nuclear half is the time period of radioactive material in which its amount remain halved.

In given question it is stated that the half life thorium-234 is 25 days. Which means after passing the 25 days the amount of thorium must be halved of original amount.

For example,

If the original concentration was 100%, than after 25 days it will be 50%.

After 50 days amount of thorium left:

Number of half life = T (elapsed) / T half life

Number of half life = 50/25

Number of half life =  2

At first half life amount of thorium left = 100/2 = 50

After second half life amount of thorium left = 50/2 = 25

Total amount decayed = 50+25 = 75

Amount left after 50 days = 100-75 = 25

25% thorium will left after 50 days.

5 0
3 years ago
Hii can someone help me pls this is the last question
lara31 [8.8K]

Answer:

B. 126

Explanation:

the scale is 1 to 42 so the scale would be:

3 cm:x cm

3 * 42 = 126 cm

8 0
2 years ago
the pressure and temperature of 10 liters of gas are doubled. if the original condition are 2 atmosphere of pressure and 400k wh
Harman [31]

Answer:

\boxed{\text{10 L}}

Explanation:

We have two pressures, two temperatures, and one volume.

This looks like a question in which we can use the Combined Gas Law to calculate the volume.

\dfrac{p_{1}V_{1}}{T_{1}} = \dfrac{p_{2}V_{2} }{T_{2}}

Data:

\begin{array}{rclrclrcl}p_{1}& =& \text{2 atm}\qquad & V_{1} &= & \text{10 L}\qquad & T_{2}& =& \text{400 K}\\p_{2}& =& \text{4 atm}\qquad & V_{2} &= & \text{?}\qquad & T_{2}& =& \text{800 K}\\\end{array}

Calculation:

\begin{array}{rcl}\dfrac{2 \times 10}{400}& =& \dfrac{4V_{2} }{800}\\\\0.050& = &0.0050V_{2}\\V_{2}& = &\mathbf{10 L}\end{array}\\\text{The final volume is }\boxed{\textbf{10 L}}

4 0
3 years ago
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