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1 year ago

Show by substitution whether the number r is a solution of the corresponding quadratic equation.

Mathematics

1 answer:

Stels [109]1 year ago

3 0

Answer:

It's choice B.

Step-by-step explanation:

When r= -11,

x^2 + 8x - 33 = (-11)^2 - 88 - 33

= 121 - 88 - 33

= 0

- so x = -11 gives a zero value and is a solution to the equation.

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Answer:

The more money you invest and the earlier you start means your retirement savings will have that much more time and potential to grow and investing early you can be able to take advantage of compound earnings.

Step-by-step explanation:

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2 years ago

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2 years ago

Use integration by parts to find the integrals in Exercise. ∫(4x-12)e-8x dx.

stepladder [879]

Answer:

$e(2x^{2} -12x)-4x^{2}+C$

Step-by-step explanation:

We have been given an indefinite integral as $\int \left(4x-12\right)e-8x\:dx$ . We are asked to find the given integral.

Let us solve our given problem.

$\int \left(4x-12\right)e\:dx-\int 8x\:dx$

Take out constant:

$e\int \left(4x-12\right)\:dx-8\int x\:dx$

$e(\int 4x\:dx -\int 12\right\:dx)-8\int x\:dx$

$e(\frac{4x^{1+1}}{2} -12x)-8*\frac{x^{1+1}}{1+1}+C$

$e(\frac{4x^{2}}{2} -12x)-8*\frac{x^{2}}{2}+C$

$e(2x^{2} -12x)-4x^{2}+C$

Therefore, our required integral would be $e(2x^{2} -12x)-4x^{2}+C$ .

5 0

2 years ago

3/4+?/2=13/4 what is answer

Otrada [13]

The answer is x=5.

Solve for x. (The question mark should be x.)

$\frac{3}{4}+\frac{x}{2}=\frac{13}{4}\\\frac{3}{4}+\frac{x}{2}-\frac{3}{4}=\frac{13}{4}-\frac{3}{4}\\\frac{x}{2}=\frac{5}{2}\\\frac{2x}{2}=\frac{5\times 2}{2}\\x=5$

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2 years ago

Help me please help me please

Nikolay [14]

Answer:

1 second

Step-by-step explanation:

$s=-5\\u=0\\v=\\a=-10\\t=t$

$\begin{aligned}\textsf{Using} \quad s & =ut+\dfrac12at^2\\ \implies -5 & =(0)t+\dfrac12(-10)t^2\\ -5 & = -5t^2\\ t^2& = 1\\ t & = \pm\sqrt{1}\\ t & = 1\: \sf s\end{aligned}$

7 0

2 years ago