<img src="https://tex.z-dn.net/?f=%28%5Cfrac%7B-7a%5E2b%5E3c%5E0%7D%7B3a%5E3b%5E4c%5E3%7D%20%29%5E-%5E4" id="TexFormula1" title=

3 years ago

"(\frac{-7a^2b^3c^0}{3a^3b^4c^3} )^-^4" alt="(\frac{-7a^2b^3c^0}{3a^3b^4c^3} )^-^4" align="absmiddle" class="latex-formula">
Can someone please give me an answer for this

Mathematics

1 answer:

ioda3 years ago

4 0

Answer:

sorry I don't speak alien

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If the quantity 4 times x squared times y squared plus 8 times x cubed times y to the fifth power all over 2 times x times y squ

motikmotik

Answer:

c=2

Step-by-step explanation:

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Answer:

x=4

Step-by-step explanation:

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3 years ago

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Which of the followeing represents the solution...<br><br> 4(9+3z)≤12+6z

julia-pushkina [17]

Solving the inequality $4(9+3z)\leq 12+6z$ we get $z\leq -4$

Step-by-step explanation:

We need to solve the inequality $4(9+3z)\leq 12+6z$

Solving:

$4(9+3z)\leq 12+6z$

Multiplying 4 with terms inside the bracket.

$36+12z\leq 12+6z$

Adding -36 on both sides:

$12z\leq 12+6z-36$

Adding -6z on both sides

$12z-6z\leq 12-36$

$6z\leq -24$

Divide both sides by 6

$z\leq -4$

So, solving the inequality $4(9+3z)\leq 12+6z$ we get $z\leq -4$

Keywords: Solving inequalities

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