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atroni [7]
3 years ago
9

To multiply a sum by a number, multiply each term inside the parentheses by the number outside the parentheses.

Mathematics
1 answer:
astra-53 [7]3 years ago
8 0
Numberical expression
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Using the table tool, create a truth table for compound statement ~p^~q.
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3 years ago
A gallon of stain is enough to cover 200 square feet of decking. Bradley has two areas of decking he would like to cover with st
Pani-rosa [81]

The expression that we need to get is:

N = \frac{(23)*(10.4) + (10.5)*(7.2)}{200}

So the correct option is the second one.

<h3>Which expression gives the number of gallons of stain Bradley will need?</h3>

We know that 1 gallon is enough to cover 200 ft².

We have two rectangular areas, one of:

23 feet by 10.4 feet, and other of 10.5 feet by 7.2 feet.

Then the total area is:

A = (23 ft)*(10.4 ft) + (10.5ft)*(7.2 ft)

The number of gallons needed is given by the quotient between the area that we want to cover, and the area that covers one gallon, so the expression is:

N = \frac{(23ft)*(10.4ft) + (10.5ft)*(7.2ft)}{200ft^2} \\\\N = \frac{(23)*(10.4) + (10.5)*(7.2)}{200}

So the corerect option is the second one.

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brainly.com/question/4344214

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7 0
2 years ago
Three times the sum of a number and 18 and is at least -30
miss Akunina [59]

Answer:

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Step-by-step explanation:

5 0
2 years ago
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If f(x) = 2x2^2 + 1 and g(x) = x^2 - 7, find (f+g) (x)
Sveta_85 [38]

(f+g)(x) = f(x) + g(x)

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= 3x² - 6

5 0
3 years ago
The perimeter of a isclose triangle is 24in and the length of the side is 4 in find the 2 other sides
Scrat [10]

Answer:

10 inches

Step-by-step explanation:

Given

Shape: Isosceles Triangle

Perimeter=24\ in

Side = 4\ in

Required

Find the length of the other two sides

Represent the other sides with x.

Since it is an isosceles triangle, 2 sides are equal.

So, we have:

x + x + 4 = 24

2x + 4 = 24

Collect Like Terms

2x = 24-4

2x = 20

Divide both sides by 2

\frac{2x}{2} = \frac{20}{2}

x = \frac{20}{2}

x = 10

<em>The other sides are 10in each</em>

4 0
2 years ago
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