Algebraically, that would be expressed as:
the probability that if you pick only one, it's defective, is 250/6700
Therefore, the probability that one is not defective is 6450/6700
a. You want all 4 to not be defective: (6450/6700)^4
b. all 100 have to be not defective: (6450/6700)^100
If you type this into a calculator, you will get about 0.022, so a probability of 2 % that all of them are not defective. As this is a very small probability, the outlet should plan with returned tires.
The numbers aren't accurate, they dont add up
Answer:
1250
Step-by-step explanation:
125
<u>* 37</u>
875
<u>+ 375</u>
1250
Answer:
B
Step-by-step explanation:
