Answer:
Hi!
The correct answer is E.
Explanation:
void change(int ar[], int low, inthigh) {
int temp;
if(low< high) { <em>// here ask if the positions low and high of the array are the same.</em>
temp= ar[low]; <em>// first, saves the element on ar[low] in temp.</em>
ar[low]= ar[high]; <em>// second, the element on ar[high] in ar[low]. First switch.</em>
ar[high]= temp; <em>// third, saves the element on temp in ar[high]. Complete switch.</em>
change(ar,low + 1, high - 1); <em>// Recursive call, adding one position to low, and subtracting one position to high. </em><em>Important: </em><em>When low and high have the same value, the recursive call will finish.</em>
}
}
Result: Switch the lower half of elements in the array with the upper half.
Answer:
A gaming mouse has more buttons to keybind to while a regular mouse is simpler
Explanation:
The most widely used forming machine arrangement is the individual section machine (or IS machine). This machine has a bank of 5–20 identical sections, each of which contains one complete set of mechanisms to make containers. ... Sections make either one, two, three or four containers simultaneously.
Answer:
public static double areaSum(Circle c1, Circle c2){
double c1Radius = c1.getRadius();
double c2Radius = c2.getRadius();
return Math.PI * (Math.pow(c1Radius, 2) + Math.pow(c2Radius, 2));
public static void main(String[] args){
Circle c1 = new Circle(6.0);
Circle c2 = new Circle(8.0);
areaSum(c1,c2);
}
Explanation:
