Answer:
Following is the expression written in "Bash script" (mixture of commands):
^\d{5}(?:[-\s]\d{4})?$
Explanation:
- ^ = For staring string (denotation).
- \d{5} = Matching 5 digits (first five unknown x's)
- (?:…) = Making Group (making group of former 5 digits)
- [-\s] = Match a hyphen or a space
(checking if a hyphen is present?)
- \d{4} = Matching 4 digits (next four unknown x's)
- …? = Pattern before it is optional
- $ = Ending of the string.(denotation)
Answer:
- low = 10
- high = 50
- count = 0
-
- for i in range(low, high + 1):
- if(i % 3 == 0 and i % 5 == 0):
- count += 1
- print(count)
Explanation:
The solution code is written in Python.
We can create low and high variables to store the lower bound and upper bound in the range (Line 1-2)
Next create a counter variable, count (Line 3).
Use a for loop to traverse through the number between lower bound and upper bound and check if the current number-i is divisible by 3 and by 5, increment the count by one.
After the loop, print the count and we can get the number of ideal integers within the range (Line 8).
Answer:
Hello the options to your question is missing here are the options
answer : 7
Explanation:
The value of the num_colors variable is 7 and this because you have to neglect the fact that there is no termination symbol at the end of the assignment operation in the code.
But when we consider the none existence of a termination symbol at the end of the assignment operation in the code, the code will generate a syntax error instead of a value.
A man mad stalemate is a probe it just has a different use.
Answer:
The correct answer to the following question is ACL name is the case sensitive.
Explanation:
ACL name is unique, alphanumeric and case sensitive that's why the router deals like the access_network, the ACCESS_NETWORK as it if they are the two separates ACL's.
That's why ACL always has the unique identities.