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1 year ago

Please solve quickly

Mathematics

1 answer:

ValentinkaMS [17]1 year ago

6 0

Answer:

62.8 inches

Step-by-step explanation:

because C= 2pi

and 10 times 2 is 20 and 20 times 3.14 is 62.8

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10x10x10x10x10x10x10 in word form

Vsevolod [243]

Answer:

10,000,000

Step-by-step explanation:

ten million

5 0

2 years ago

Read 2 more answers

How do I graph this?

vfiekz [6]

See attachment of the graph of the inequalities x + 7y ≤ 49 and 6x + y ≤ 48

<h3>How to graph the inequalities?</h3>

The inequalities are given as:

x + 7y ≤ 49

6x + y ≤ 48

The domain and the range are:

x ≥ 0

y ≥ 0

This means that, we plot the inequalities x + 7y ≤ 49 and 6x + y ≤ 48 under the domain and the range x ≥ 0 and y ≥ 0

See attachment of the graph of the inequalities x + 7y ≤ 49 and 6x + y ≤ 48

Read more about inequalities at:

brainly.com/question/25275758

#SPJ1

6 0

1 year ago

2x=54 Which of the following properties is included in the justification for the steps used to solve the equation? A. division p

Bas_tet [7]

The answer will be A. Division property of equality

7 0

3 years ago

Can I get help with finding the Fourier cosine series of F(x) = x - x^2

trapecia [35]

Assuming you want the cosine series expansion over an arbitrary symmetric interval $[-L,L]$ , $L\neq0$ , the cosine series is given by

$f_C(x)=\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos nx$

You have

$a_0=\displaystyle\frac1L\int_{-L}^Lf(x)\,\mathrm dx$
$a_0=\dfrac1L\left(\dfrac{x^2}2-\dfrac{x^3}3\right)\bigg|_{x=-L}^{x=L}$
$a_0=\dfrac1L\left(\left(\dfrac{L^2}2-\dfrac{L^3}3\right)-\left(\dfrac{(-L)^2}2-\dfrac{(-L)^3}3\right)\right)$
$a_0=-\dfrac{2L^2}3$

$a_n=\displaystyle\frac1L\int_{-L}^Lf(x)\cos nx\,\mathrm dx$

Two successive rounds of integration by parts (I leave the details to you) gives an antiderivative of

$\displaystyle\int(x-x^2)\cos nx\,\mathrm dx=\frac{(1-2x)\cos nx}{n^2}-\dfrac{(2+n^2x-n^2x^2)\sin nx}{n^3}$

and so

$a_n=-\dfrac{4L\cos nL}{n^2}+\dfrac{(4-2n^2L^2)\sin nL}{n^3}$

So the cosine series for $f(x)$ periodic over an interval $[-L,L]$ is

$f_C(x)=-\dfrac{L^2}3+\displaystyle\sum_{n\ge1}\left(-\dfrac{4L\cos nL}{n^2L}+\dfrac{(4-2n^2L^2)\sin nL}{n^3L}\right)\cos nx$

4 0

3 years ago

50 POINTS !! PLEASE HELP !! ILL GIVE BRAINLIEST TO THE RIGHT ANSWERS.

maks197457 [2]

Answer:

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Trigonometry

[Right Triangles Only] Pythagorean Theorem: a² + b² = c²

a is a leg
b is another leg
c is the hypotenuse

Step-by-step explanation:

Step 1: Define

Identify variables

Leg a = a

Leg b = 12

Hypotenuse c = 20

Step 2: Solve for a

Substitute in variables [Pythagorean Theorem]: a² + 12² = 20²
Evaluate exponents: a² + 144 = 400
[Subtraction Property of Equality] Isolate a term: a² = 256
[Equality Property] Square root both sides: a = 16

3 0

3 years ago

Read 2 more answers

Please solve quickly ​

Please solve quickly