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Debora [2.8K]
2 years ago
10

Which of the following is a solution of the system x – 2y < 4 and y > – 2x – °5?

Mathematics
1 answer:
Nutka1998 [239]2 years ago
8 0

Answer: B

Step-by-step explanation:

Given the two systems of inequality to be:

x – 2y < 4

Rearrange the equation,

X - 2y < 4

-2y < 4 - x

The sign will change as we divide both sides by -2

Y > -2 + x/2

Y > x/2 - 2 ...... (1)

and

y > – 2x – 5 ..... (2)

Multiply (1) by 2 and (2) by 1/2

2y > x - 4

y/2 > -x - 5/2

Since the inequality sign of the two are the same, you can eliminate x by addition.

2 1/2 y > - 4 5/2

Change mixed fraction to improper fraction.

5y/2 > -13/2

Cross multiply

10y > -26

y > -26/10

y > - 2.6

Base on the value got for y, the correct answer is B ( -8, 2 ) because only option B and D has negative value for x and y is not equal to zero.

You confirm by plugging in the value in the two inequality equations.

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What can multiply to get -36 and add to get -40
Sloan [31]

4*-9+-4= -40

-36-4= -40

-40=-40

I hope that's help:)


6 0
3 years ago
A rectangular cake pan has a volume of
enot [183]

Step-by-step explanation:

volume of a rectangular pan = length of the pan × width of the pan × height of the pan

V=l.b.h

234=9.13.h

h=234/9×13

h= 2in.

hope this helps you.

7 0
2 years ago
Read 2 more answers
At Niagra High, Mr. Borton bought 4 student tickets and 2 adult tickets for the high school musical which cost $64. then Mrs. Ge
balandron [24]

Answer:

Each student ticket costs $8.33

Each adult ticket costs $15.34

Step-by-step explanation:

At Niagra High, Mr. Borton bought 4 student tickets and 2 adult tickets for the high school musical which cost $64. then Mrs. Gelvoria bought 3 student tickets and 3 adult tickets for the show and it cost her $72. How much are each type of tickets?​

s = cost of each student ticket

a = cost of adult ticket

Our system of equations:

4s + 2a = 64

3s + 3a = 71

-3(4s + 2a = 64) ==> -12s - 6a = -192

2(3s + 3a = 71) ==>     6s + 6a = 142

-12s - 6a = -192

  6s + 6a = 142

-6s = -50

/-6      /-6

s = $8.33 (the cost of each student ticket)

Now, let's find the cost of each adult ticket:

4s + 2a = 64

4(8.33) + 2a = 64

33.32 + 2a = 64

-33.32         -33.32

2a = 30.68

/2        /2

a = 15.34 (the cost of each adult ticket)

(x, y) ==> (8.33, 15.34)

Check your answer:

4s + 2a = 64

4(8.33) + 2(15.34) = 64

33.32 + 30.68 = 64

64 = 64

This statement is true

Hope this helps!

8 0
2 years ago
Gloria had two sets of alphabet cards (A–Z). She mixed the two sets together to form a single stack of cards. Then Gloria drew t
grin007 [14]
She has 52 card all together so she has a probability of drawing on the first draw 4 L's or R's because their are two sets of alphabet cards.  So that is 4/52 or 1/13 to the lowest term.  Second turn she only has 51 cards to draw from and still has 4 L's and R's so that would be 4/51 and on the third try she has only 50 cards left so that would be 4/50 or 2/25 to the lowest term.  Now multiply all three factions 1/13 x 4/51 x 2/25 = 8/16575 meaning out of the three draws she has a probability of getting a L or R, 8 out of 16575 each draw.
3 0
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jek_recluse [69]

Answer:

If it counts as a question, lol sure, I'd love to help

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