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Debora [2.8K]
2 years ago
10

Which of the following is a solution of the system x – 2y < 4 and y > – 2x – °5?

Mathematics
1 answer:
Nutka1998 [239]2 years ago
8 0

Answer: B

Step-by-step explanation:

Given the two systems of inequality to be:

x – 2y < 4

Rearrange the equation,

X - 2y < 4

-2y < 4 - x

The sign will change as we divide both sides by -2

Y > -2 + x/2

Y > x/2 - 2 ...... (1)

and

y > – 2x – 5 ..... (2)

Multiply (1) by 2 and (2) by 1/2

2y > x - 4

y/2 > -x - 5/2

Since the inequality sign of the two are the same, you can eliminate x by addition.

2 1/2 y > - 4 5/2

Change mixed fraction to improper fraction.

5y/2 > -13/2

Cross multiply

10y > -26

y > -26/10

y > - 2.6

Base on the value got for y, the correct answer is B ( -8, 2 ) because only option B and D has negative value for x and y is not equal to zero.

You confirm by plugging in the value in the two inequality equations.

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Bonjour, pouvez vous m'aidez svp ^^ Ci-contre, [MH] est une hauteur du triangle MAT. Éva affirme que le périmètre du triangle MA
Anna35 [415]

Cette question est incomplète.

Question complète

Exercer:

En face, [MH] est une hauteur du triangle MAT.

a.Calculer MH, puis HT.

b. Eva dit: "".

A-t-elle raison? Expliquer.

MA = 7,8cm

MT = 7,5cm

AH = 3cm

Answer:

La réponse d'Eva est incorrecte

Step-by-step explanation:

Nous résolvons les questions abive en utilisant le théorème de Pythagore

c² = a² + b²

a) Application de la formule ci-dessus:

Étape 1

Trouver MH

MA² = MH² + HA²

7,8² = MH² + 3²

MH² = 60,84-9

MH² = 51,84

MH = √51,84

MH = 7,2 cm

Étape 2

Résoudre pour HT

MT² = MH² + HT²

7,5² = 7,2² + HT²

HT² = 56,25 à 51,84

HT = √4,41

HT = 2,1 cm

b) La formule pour le périmètre du triangle MAT =

MA + MT + AH + HT

= 7,8 + 7,5 + 2,1 + 3 = 20,4 cm

Le périmètre du triangle MAT est de 20,4 cm

Donc, la réponse d'Eva est incorrecte

8 0
3 years ago
The heights of women aged 20 to 29 are approximately Normal with mean 64 inches and standard deviation 2.7 inches. Men the same
masha68 [24]

Answer: The z-scores for a woman 6 feet tall is 2.96 and the z-scores for a a man 5'10" tall is 0.25.

Step-by-step explanation:

Let x and y area the random variable that represents the heights of women and men.

Given : The heights of women aged 20 to 29 are approximately Normal with mean 64 inches and standard deviation 2.7 inches.

i.e. \mu_1 = 64   \sigma_1=2.7

Since , z=\dfrac{x-\mu}{\sigma}

Then, z-score corresponds to  a woman 6 feet tall (i.e. x=72 inches).

[∵  1 foot = 12 inches , 6 feet = 6(12)=72 inches]

z=\dfrac{72-64}{2.7}=2.96296296\approx2.96

Men the same age have mean height 69.3 inches with standard deviation 2.8 inches.

i.e. \mu_2 = 69.3   \sigma_2=2.8

Then, z-score corresponds to a man 5'10" tall (i.e. y =70 inches).

[∵  1 foot = 12 inches , 5 feet 10 inches= 5(12)+10=70 inches]

z=\dfrac{70-69.3}{2.8}=0.25

∴ The z-scores for a woman 6 feet tall is 2.96 and the z-scores for a a man 5'10" tall is 0.25.

6 0
3 years ago
Use the line tool to graph the equation on the coordinate plane.<br><br> y=−2x
sertanlavr [38]
Hey there,

Your answer would be in the attachment above.

Hope this helps.

~Jurgen

(Any questions?, Just comment below) =)

5 0
3 years ago
Read 2 more answers
This cubiod is made from 6 small cubes write how many small cubes there are in this cubiod
BARSIC [14]

Answer:

16 I guess.

Step-by-step explanation:

lolololololol?

7 0
2 years ago
The area of a square for on a scale drawing of 100 square centimeters and the scale drawing to 1 cm: 2 feet what is the area of
lilavasa [31]

Answer:

1.\boxed{\text{400 ft}^{2}}; 2. \boxed{\frac{1}{3716}}

Step-by-step explanation:

Step 1. Calculate the area of the floor

If the area A₁ of a square floor on the scale drawing is 100 cm², the length of a side is 10 cm.

The side length l of the actual floor is  

l = 10 cm × (2 ft/1 cm) = 20 ft

The area A₂ of the floor is  

A = l² = (20 ft)² = \boxed{\text{400 ft}^{2}}\\

Step 2. Calculate the area ratios

We must express both areas in the same units.  

Let's express the area of the room in square centimetres.

l = 20 ft ×  (12 in/1 ft) = 240 in

l = 240 in × (2.54 cm/1 in) = 609.6 cm

A₂ = l² = (609.6 cm)² = 371 612 cm²

The area A₁ on the scale drawing is 100 cm².

The ratio of the areas is

\frac{A_{1}}{ A_{2}} = \frac{100}{371612} = \frac{1 }{3716}\\

The ratio of the area in the drawing to the actual area is \boxed{\frac{1}{3716}}

8 0
3 years ago
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