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salantis [7]
2 years ago
13

If it is 9'oclock now what time will it be in 16hours time​

Mathematics
1 answer:
Oksi-84 [34.3K]2 years ago
7 0

Answer:

1 AM

Step-by-step explanation:

9AM(start time) to 9PM = 12 hours + the other 4 Hours, 10PM, 11PM, 12PM, 1AM(end time).

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Hello i need help on it ​
sweet-ann [11.9K]

Answer:

the answer will be 29 :)

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2 years ago
What is the answer for this (3^56^8)(3^96^10)
sweet-ann [11.9K]
The answer is

3^66483360316461674016
6 0
3 years ago
Graph a triangle ABC and perform a translation of (x + 4, y − 3) to create triangle A′B′C′.
LiRa [457]

Answer:

to describe the transformation in words you could say, triangle ABC was moved to the right 4 times and down 3 times.

4 0
3 years ago
A w=-8<br> B w=-5 <br> C w=5<br> D w=8
algol [13]

Answer:

D

Step-by-step explanation:

Plug in every scenario, in see if it equal to each other.

D is the only one that is equal.

8 0
3 years ago
The mean preparation fee H&amp;R Block charged retail customers in 2012 was $183 (The Wall Street Journal, March 7, 2012). Use t
astraxan [27]

Answer:

a)0.6192

b)0.7422

c)0.8904

d)at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.

Step-by-step explanation:

Let z(p) be the z-statistic of the probability that the mean price for a sample is within the margin of error. Then

z(p)=\frac{ME*\sqrt{N}}{s } where

  • Me is the margin of error from the mean
  • s is the standard deviation of the population
  • N is the sample size

a.

z(p)=\frac{8*\sqrt{30}}{50 } ≈ 0.8764

by looking z-table corresponding p value is 1-0.3808=0.6192

b.

z(p)=\frac{8*\sqrt{50}}{50 } ≈ 1.1314

by looking z-table corresponding p value is 1-0.2578=0.7422

c.

z(p)=\frac{8*\sqrt{100}}{50 } ≈ 1.6

by looking z-table corresponding p value is 1-0.1096=0.8904

d.

Minimum required sample size for 0.95 probability is

N≥(\frac{z*s}{ME} )^2 where

  • N is the sample size
  • z is the corresponding z-score in 95% probability (1.96)
  • s is the standard deviation (50)
  • ME is the margin of error (8)

then N≥(\frac{1.96*50}{8} )^2 ≈150.6

Thus at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.

7 0
3 years ago
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