Answer:
<em>The uniform rate of depreciation is $56,333 per year, or 11% per year.</em>
Step-by-step explanation:
<u>Rate of Depreciation</u>
If some object has a certain value P and after some time t its value decreases to Q, the rate of depreciation is a measure of how much its value changed per unit time.
It can be calculated as:
It can also be expressed as a percentage, dividing the previous value by P.
The school bus reduces its value from $512,000 to $343,000 in 3 years, thus:
R = 56,333 $/year
Expressed as a percentage:
R = 56,333 / 512,000 = 0.11
R = 11%/year
The uniform rate of depreciation is $56,333 per year, or 11% per year.
2(z - 5) + (z - 8) =
= 2z - 10 + z - 8 =
= 2z + z - 10 - 8 = <u>3</u><u>z</u><u> </u><u>-</u><u> </u><u>1</u><u>8</u> ← the end
Answer:
Let's begin by writing the mathematical equations given by the sentences.
Let X = smaller number
Let Y = larger number
The first sentence tells us
X + Y = 38
The second sentence tells us
X = Y/3 + 6
Since you weren't given a specific method to use, you can use either the substitution method or the elimination(addition) method, whichever works best for you.
Since the 2nd equation has the X isolated, I'm going to isolate the X in the first equation,
X = 38 - Y
Since both equations are equal to X, I can set them equal to one another and solve for Y.
Y/3 + 6 = 38 - Y
Y + 18 = 114 - 3Y
4Y = 96
Y = 24
Then use either of the two original equations to solve for X
X + Y = 38
X + 24 = 38
X = 14
Step-by-step explanation:
PLS MAKE ME AS BRAINLIST
Answer:
10x - 3
Step-by-step explanation:
First, distribute 2 to all terms within the second parenthesis:
2(3x + 1) = (2 * 3x) + (2 * 1) = 6x + 2
4x - 5 + 6x + 2
Combine like terms (terms with the same amount of variables).
4x + 6x + 2 - 5
(4x + 6x) + (2 - 5)
10x + (-3)
10x - 3
10x - 3 is your answer.
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Answer:
-5
Step-by-step explanation:
