Answer:
For interquartile range, you will need to find the range of the boxes, and not the line since for the lower quartile is 5.5 and the higher qaurtile is 7, the interquatile range is 1.5
Step-by-step explanation:
1- 3(n+5)= -8
-3n-15= -9
-3n = 6
n= -2
The equation of a linear function: y = mx + b
x = y - 3 → y - 3 = x <em>add 3 to both sides</em>
y = x + 3 <em>it's a linear function!</em>
y = x³ + 2 NOT, because we have x³
y = 6x² NOT, because we have x²
y = 2/(3x) NOT, because x is in denominator.
Answer:
Option A. the solution a = -4 is an extraneous solution.
Step-by-step explanation:
Lets solve the radical equation to get the potential solutions.
√(a + 5) = (a + 3)
By squaring terms on both the sides
[√(a + 5)]² = (a +3)²
(a + 5) = (a + 3)²
(a + 5) = a² + 6a + 9
0 = a² + 6a + 9 - a - 5
a² + 5a + 4 = 0
a² + 4a + a + 4 + 0
a(a + 4) + 1(a + 4) = 0
(a + 1)(a + 4) = 0
a = -1 or a = -4
Now if we put the value of a = - 4 in the radical equation then we get
√(-4 + 5) = (-4 + 3)
√1 = -1
1 = -1 ( Therefore a = -4 is not the solution)
Now by putting a = -1
√(-1 +5) = -1 + 3
√4 = 2
2 = 2 which shows the equal relation.
Therefore a = -4 is an extraneous solution.
Option A. is the correct option.