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2 years ago

PLEASE HELP I WILL GIVE BRAINLIEST How many students are represented in this histogram?

Mathematics

2 answers:

Lilit [14]2 years ago

7 0

I don't think you need to know you just need to write 1/2/3/4/5/6/7/8/9 because that's what there

Romashka-Z-Leto [24]2 years ago

6 0

Answer:

22 student are represented in that histogram.

Step-by-step explanation:

correct me if wrong please

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Please help!!!! 30 pts

Sedbober [7]

We are given equation:

5/6 x -2 = -2/3 x +1.

Note: when we have fracions in an equation, we always try to get rid fractions by removing denominator parts.

In the given equation we have 6 and 3 in denominator. So, we need to find the common denominator (lowest common denomiantor) of 6 and 3.

The lowest common denomiantor of 6 and 3 is 6.

So, equation is being multiplied by 6 on both sides.

Therefore,

Step 1) Multiply each side by LCD of fractions.

6 ( 5/6 x -2 ) = 6 (-2/3 x +1)

Step 2) Use distributive property to simplify above step, we get

6* 5/6 x = 5x

6 * -2 = -12

6 * -2/3 x = -4x and

6 * 1 = 6.

Therefore, we get

5x - 12 = -4x + 6 on simplifying second step.

Step 3) We use Addition property of Equality in third step.

Because we have -4x on right side, and the reverse operation of subtraction is addition.

5x - 12 = -4x + 6

+4x +4x Step 4) Here we just did simplification of above step.

____________________

9x -12 = 6

+12 +12 Step 5) Again applied Addition property of Equality to get rid -12 from left side.

_______________

9x = 18 Step 6) Here we just did simplification of above step.

Step 7) Because 9 is being multiplied with x on left side. To get rid 9 from left side we need to apply reverse operation of multiplication.

Therefore, Division property of equality is used there by dividing 9 on both sides.

9x/9 = 18/9

Step 8) Again did simplification of above step.

x=2 Final answer.

3 0

3 years ago

Read 2 more answers

The diagram shows a sector of a circle radius 10cm

Yuki888 [10]

Answer:

$\text{Perimeter of sector = 43.6 (Rounded to the nearest tenth.)}$

Step-by-step explanation:

$\text{Perimeter of the sector = Radius + arc length + radius}$

$\text{Radius = 10 cm}$

$\text{Perimeter of the sector = 10 + arc length + 10 }$

$\text{Perimeter of the sector = 20 + arc length }$

$\text{arc length = (sector angle/ 360 ) * perimeter of the circle}$

$\text{Perimeter of a circle }=2\pi r$

$\text{sector angle} = 135$

$\text{arc length} = (135/ 360 ) * 2\pi (10)$

$= (3/8) 20\pi$

$= 15\pi /2$

$\text{Using }\pi =3.14$

$= 15 * 3.14 /2$

$= 23.55$

$\text{Perimeter of the sector = 20 + 23.55}$

$= 43.55$

$= 43.6 cm$

$\text{perimeter of the sector = 43.6 cm }$

8 0

2 years ago

The answer is 585 R4 and could also be written as 585 4/8. Simplify the answer.

Digiron [165]

Answer:

585 1/2 ?

Step-by-step explanation:

i dont know if you put the whole question but i simplified 4/8 and got 1/2.

so i guess the answer your looking for is 585 1/2 ...

4 0

3 years ago

Find the six trig function values of the angle 240*Show all work, do not use calculator

-BARSIC- [3]

Solution:

Given:

$240^0$

To get sin 240 degrees:

240 degrees falls in the third quadrant.

In the third quadrant, only tangent is positive. Hence, sin 240 will be negative.

$sin240^0=sin(180+60)$

Using the trigonometric identity;

$sin(x+y)=sinx\text{ }cosy+cosx\text{ }siny$

Hence,

$\begin{gathered} sin(180+60)=sin180cos60+cos180sin60 \\ sin180=0 \\ cos60=\frac{1}{2} \\ cos180=-1 \\ sin60=\frac{\sqrt{3}}{2} \\ \\ Thus, \\ sin180cos60+cos180sin60=0(\frac{1}{2})+(-1)(\frac{\sqrt{3}}{2}) \\ sin180cos60+cos180sin60=0-\frac{\sqrt{3}}{2} \\ sin180cos60+cos180sin60=-\frac{\sqrt{3}}{2} \\ \\ Hence, \\ sin240^0=-\frac{\sqrt{3}}{2} \end{gathered}$

To get cos 240 degrees:

240 degrees falls in the third quadrant.

In the third quadrant, only tangent is positive. Hence, cos 240 will be negative.

$cos240^0=cos(180+60)$

Using the trigonometric identity;

$cos(x+y)=cosx\text{ }cosy-sinx\text{ }siny$

Hence,

$\begin{gathered} cos(180+60)=cos180cos60-sin180sin60 \\ sin180=0 \\ cos60=\frac{1}{2} \\ cos180=-1 \\ sin60=\frac{\sqrt{3}}{2} \\ \\ Thus, \\ cos180cos60-sin180sin60=-1(\frac{1}{2})-0(\frac{\sqrt{3}}{2}) \\ cos180cos60-sin180sin60=-\frac{1}{2}-0 \\ cos180cos60-sin180sin60=-\frac{1}{2} \\ \\ Hence, \\ cos240^0=-\frac{1}{2} \end{gathered}$

To get tan 240 degrees:

240 degrees falls in the third quadrant.

In the third quadrant, only tangent is positive. Hence, tan 240 will be positive.

$tan240^0=tan(180+60)$

Using the trigonometric identity;

$tan(180+x)=tan\text{ }x$

Hence,

$\begin{gathered} tan(180+60)=tan60 \\ tan60=\sqrt{3} \\ \\ Hence, \\ tan240^0=\sqrt{3} \end{gathered}$

To get cosec 240 degrees:

$\begin{gathered} cosec\text{ }x=\frac{1}{sinx} \\ csc240=\frac{1}{sin240} \\ sin240=-\frac{\sqrt{3}}{2} \\ \\ Hence, \\ csc240=\frac{1}{\frac{-\sqrt{3}}{2}} \\ csc240=-\frac{2}{\sqrt{3}} \\ \\ Rationalizing\text{ the denominator;} \\ csc240=-\frac{2}{\sqrt{3}}\times\frac{\sqrt{3}}{\sqrt{3}} \\ \\ Thus, \\ csc240^0=-\frac{2\sqrt{3}}{3} \end{gathered}$

To get sec 240 degrees:

$\begin{gathered} sec\text{ }x=\frac{1}{cosx} \\ sec240=\frac{1}{cos240} \\ cos240=-\frac{1}{2} \\ \\ Hence, \\ sec240=\frac{1}{\frac{-1}{2}} \\ sec240=-2 \\ \\ Thus, \\ sec240^0=-2 \end{gathered}$

To get cot 240 degrees:

$\begin{gathered} cot\text{ }x=\frac{1}{tan\text{ }x} \\ cot240=\frac{1}{tan240} \\ tan240=\sqrt{3} \\ \\ Hence, \\ cot240=\frac{1}{\sqrt{3}} \\ \\ Rationalizing\text{ the denominator;} \\ cot240=\frac{1}{\sqrt{3}}\times\frac{\sqrt{3}}{\sqrt{3}} \\ \\ Thus, \\ cot240^0=\frac{\sqrt{3}}{3} \end{gathered}$

5 0

1 year ago

Music Jeremy spent $33 on 3 CDs .At this a rate how much would 5 CDs cost

kvasek [131]

Question: Jeremy spent $33 on 3 CDs .At this a rate how much would 5 CDs cost?

Answer: I think the answer is 55$.

Hope this helps. c;

8 0

3 years ago

Read 2 more answers