A diagonal of a cube measures
1 answer:
Answer: 7cm
Step-by-step explanation:
Use pythagorean theorum:
Variables:
Let the edge = A
Face diagonal (F) = 10cm
Inner diagonal (I) = sqrt(150) cm
A^2 = I^2 - F^2
A^2 = [sqrt(150)]^2 - 10^2
A^2 = 150 - 100
A^2 = 50
A = sqrt(50)
A = 7.0710678 cm
A = 7cm (to the nearest tenth)
so, length of an edge = 7cm
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