Question

A diagonal of a cube measures

Answer 1

Answer: 7cm

Step-by-step explanation:

Use pythagorean theorum:

Variables:

Let the edge = A

Face diagonal (F) = 10cm

Inner diagonal (I) = sqrt(150) cm

A^2 = I^2 - F^2

A^2 = [sqrt(150)]^2 - 10^2

A^2 = 150 - 100

A^2 = 50

A = sqrt(50)

A = 7.0710678 cm

A = 7cm (to the nearest tenth)

so, length of an edge = 7cm