Answer:
The answer is "Option A".
Explanation:
The Dot matrix printer is also known as an impact matrix printer. It is a multi-part form printer because it prints data on paper. This printer uses a hammer and a ribbon printer, that shapes pictures from dots. and other options are not correct, that can be described as follows:
- In option B, daisy-wheel printer prints data on printer only one side that's it is not correct.
- In option C, the Inkjet printer is capable to print data in multi-part forms, but this printer does not data in continuous forms.
- In option D, the color printer allows you to print data in color format like images, graphs, and banner. It prints data only on one side, that's why it is not correct.
With four processing cores, we get a speedup of 1.82 times.
<h3>
What is Amdahl's Law?</h3>
Amdahl's law exists as a formula that provides the theoretical speedup in latency of the implementation of a task at a fixed workload that can be expected of a system whose resources exist improved.
Amdahl's law exists that, in a program with parallel processing, a relatively few instructions that hold to be completed in sequence will have a limiting factor on program speedup such that adding more processors may not complete the program run faster.
Amdahl's law stands also known as Amdahl's argument. It is utilized to find the maximum expected progress to an overall system when only part of the system exists improved. It is often utilized in parallel computing to indicate the theoretical maximum speed up utilizing multiple processors.
Hence, With four processing cores, we get a speedup of 1.82 times.
To learn more about Amdahl's Law refer to:
brainly.com/question/16857455
#SPJ4
Answer:
see explaination
Explanation:
I made use of python program to solve this.
text file name with fun.txt.
6 fun. 3 hello 10 <> 2 25 4 wow!
Program code:
import re
file = open('fun.txt','r') #for reading file
strings="" #declaring empty string
for k in file:
strings=strings+k #all character in file is storing in strings variable for do operations
pattern = '\s' #for pattern \s is for space
result = re.split(pattern, strings) #split the string with space
for k in range(len(result)): #loop through the list of string
if(k%2) == 0: #checking for integer to time of string
p=int(result[k])
print(result[k+1] *p) #print times of the string(k+1)
Check attachment for output
