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2 years ago

Find the area and volume of a 11 inch cube (pls write do the equation in steps)

Mathematics

1 answer:

Cerrena [4.2K]2 years ago

6 0

Answer:

1331 inches cubed

Step-by-step explanation:

V=LHW

since it is a cube, the length, height, and width will all be the same; 11 inches. You have to multiply 11 by 11 by 11, which equals 1331.

Hope this helped!

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Trigonometric ratios

const2013 [10]

Answer:

(√3+1.4)m

Step-by-step explanation:

By forming a right triangle, we can see that the angle of elevation is 30°.

In a 30-60-90 triangle, the side opposite the 30° is the other leg multiplied by 1/√3.

x= $\frac{3}{\sqrt{3} } =\frac{3\sqrt{3} }{\sqrt{3}*\sqrt{3} } =\frac{3\sqrt{3} }{3} =\sqrt{3}$

The height of the pole is (√3+1.4)m

8 0

3 years ago

Verify that each equation is an identity (1 - sin^(2)((x)/(2)))/(1+sin^(2)((x)/(2)))= (1+cosx)/(3-cosX)

Allisa [31]

Answer:

Given that we have;

$sin \left (\dfrac{x}{2} \right ) = \sqrt{\dfrac{1 - cos (x)}{2} }$

By the application of the law of indices and algebraic process of adding a and subtracting a fraction from a whole number, we have;

$\therefore \dfrac{\left ( 1 - sin^2 \left (\dfrac{x}{2} \right ) \right )}{\left ( 1 + sin^2 \left (\dfrac{x}{2} \right ) \right )} =\dfrac{\left ( \dfrac{1 + cos (x)}{2} \right)}{\left (\dfrac{3 - cos (x)}{2} \right ) } =\dfrac{\left ( 1 + cos (x))}{(3 - cos (x))}$

Step-by-step explanation:

An identity is a valid or true equation for all variable values

The given equation is presented as follows;

$\dfrac{\left ( 1 - sin^2 \left (\dfrac{x}{2} \right ) \right )}{\left ( 1 + sin^2 \left (\dfrac{x}{2} \right ) \right )} =\dfrac{\left ( 1 + cos (x))}{(3 - cos (x))}$

From trigonometric identities, we have;

$sin \left (\dfrac{x}{2} \right ) = \sqrt{\dfrac{1 - cos (x)}{2} }$

$\therefore sin^2 \left (\dfrac{x}{2} \right ) = \dfrac{1 - cos (x)}{2}$

$1 - sin^2 \left (\dfrac{x}{2} \right ) = 1 - \dfrac{1 - cos (x)}{2} = \dfrac{2 - (1 - cos (x))}{2} = \dfrac{1 + cos (x))}{2}$

$1 + sin^2 \left (\dfrac{x}{2} \right ) = 1 + \dfrac{1 - cos (x)}{2} = \dfrac{2 + 1 - cos (x))}{2} = \dfrac{3 - cos (x))}{2}$

$\therefore \dfrac{\left ( 1 - sin^2 \left (\dfrac{x}{2} \right ) \right )}{\left ( 1 + sin^2 \left (\dfrac{x}{2} \right ) \right )} =\dfrac{\left ( 1 + cos (x))}{(3 - cos (x))}$

3 0

3 years ago

Yoooooo can somebody help me

elena55 [62]

The numeric value of the expression d² + 3a + 6 + a when a = 2 and d = 5 is of 39.

<h3>How to find the numeric value of an expression?</h3>

The numeric value of a function is found replacing each instance of a variable by the value of the input for which we want to find the numeric value.

For this problem, the expression is given by:

d² + 3a + 6 + a

We want to find the numeric value when a = 2 and d = 5, hence:

5² + 3(2) + 6 + 2 = 25 + 6 + 6 + 2 = 39.

More can be learned about the numeric values of a function at brainly.com/question/14556096

#SPJ1

6 0

2 years ago

What are the domain and range of the function f(x)=-3(x-5)2 +4?

Xelga [282]

Answers:

Domain is $(-\infty, \infty)$

Range is $(-\infty, 4]$

============================================

Explanation:

We can replace x with any real number we want. We don't have any restrictions to worry about since there are no division by zero issues for instance. Also, there isn't any issues of things like taking the square root of a negative number.

Therefore, the domain is the set of all real numbers which translates to the interval notation of $(-\infty, \infty)$

This interval notation can be thought of as $-\infty < x < \infty$

----------------------------

The range on the other hand isn't the set of all real numbers. It might help to graph this parabola (see below). You should see that the highest point occurs at the vertex (5, 4). This then tells us that the largest y can get is y = 4.

In other words, y = 4 or y can be smaller than this.

In symbols, we would say the range is $y \le 4$ and that translates to the interval notation of $(-\infty, 4]$

The curved parenthesis always goes with either infinity. The square bracket says "include the endpoint 4 as part of the interval".

4 0

3 years ago

Geometry help wanted will give 50 points .

Dvinal [7]

Okay, I will try to help you the best I can!!

8 0

3 years ago