1. You con solve the quadratic equation x^2+20x+100=50<span> by following the proccedure below:
2. Pass the number 50 from the right member to the left member. Then you obtain:
x^2+20x+100-50=0
</span><span> x^2+20x+50=0
</span><span>
3. Then, you must apply the quadratic equation, which is:
x=(-b±√(b^2-4ac))/2a
</span><span>x^2+20x+50=0
</span><span>
a=1
b=20
c=50
4. Therefore, when you substitute the values into the quadratic equation and simplify ir, you obtain that the result is:
-10</span>±5√2 (It is the last option).
Answer:
82
Step-by-step explanation:
hope this helps you man
Answer:
b
Step-by-step explanation:
its correct
Answer:
105.
Step-by-step explanation:
21+21+21+21+21=105.
Answer:
7/96
Step-by-step explanation:
to find the answer you need to multiply both numerators together and put that over the product of the denominators, this is going to leave you with a fraction smaller than the original fractions. that is normal, because you are multiplying terms smaller than one together. same applies to decimals less than one
