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san4es73 [151]
3 years ago
12

A.When are students first expected to work with picture and bar graphs? Give the grade level, the domain and summarize the stand

ard that expresses this expectation.
b. At the next grade level, students are expected to expand their understanding of bar graph to a scaled bar graph. Give the grade level, the domain and summarize the standard that expresses this expectation.

c. Sketch examples of a "single-unit scale bar graph" and a "scaled bar graph" using the techniques from this section to illustrate the standards in parts a. and b. Explain your thinking.

This is for MTH212 I am just confused with these problems.
Mathematics
1 answer:
Sergeu [11.5K]3 years ago
8 0
Not sure if C. But it's my guess...
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s344n2d4d5 [400]
<span>The answer is B) 160
First find exterior angle
360 / 18 = 20
Interior angle = 180 - 20 = 160

</span>
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3 years ago
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Multiple Choice What is the sum of five-sixths + start fraction 2 over 3 end fraction? A. one and one-third B. One and one half
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Answer:

B

Step-by-step explanation:

\frac{5}{6} +\frac{2}{3} \\\\=\frac{5}{6}+\frac{2*2}{2*3}  \\\\=\frac{5}{6}+\frac{4}{6} \\\\=\frac{5+4}{6} \\\\=\frac{9}{6} \\\\=\frac{3*3}{3*2} \\\\=\frac{3}{2}

=\frac{2+1}{2} \\\\=\frac{2}{2}+\frac{1}{2}  \\\\=1+\frac{1}{2}

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4 years ago
What is the coefficient in the following expression?
Y_Kistochka [10]
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3 years ago
Please answer and explain how you did it.
alukav5142 [94]

Refer to the attached image.

Given: m \angle A = 65^\circ and measure of exterior angle at C = 117^\circ.

We have to determine the measure of angle B and angle BCA.

By applying exterior angle property of the triangle which states:

"An exterior angle of a triangle is equal to the sum of the opposite interior angles".

So, exterior angle C = m \angle A + m \angle B

117^\circ = 65^\circ+ m \angle B

m \angle B = 52^\circ

Now, applying angle sum property in triangle ABC which states:

"The sum of all the angles of a triangle is 180 degrees".

m \angle A + m \angle B + m \angle BCA = 180^\circ

65^\circ + 52^\circ + m \angle BCA = 180^\circ

117^\circ + m \angle BCA = 180^\circ

m \angle BCA = 180^\circ - 117^\circ

m \angle BCA =63^\circ

Therefore, the measure of m \angle B = 52^\circ and m \angle BCA =63^\circ.

8 0
3 years ago
Math help guys how wouls i work this out
Andrei [34K]

8 > 7 + \frac{x}{6}   Subtract 7 from both sides

1 > \frac{x}{6}   Multiply both sides by 6

6 > x   Flip it around so it's easier to read

x < 6

You can graph your answer by drawing an open circle at the 6 and coloring the line to the left. The circle should be open, because x is <em>less than 6</em>, not less than or equal to. You would color to the left to show that x can be anything less than 6.

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3 years ago
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