The diameter of a circle is 4 ft. Find its area to the nearest tenth.

Can someone help me 19 to 32

andreev551 [17]

Answer:

simple just divide it by finding the reciprocal for the second number

ex: 2/4=4/2

then multiply

Step-by-step explanation:

8 0

3 years ago

What are the slope and the y-intercept of the linear function that is represented by the graph?

Naddik [55]

The slope is the change in y over the change in x.

The first number in the parentheses is the x value, the second number is the y value.

Slope = (0-3) / (4-0)

Slope = -3/4

The y intercept is the y value when x is 0.

The given point (0,3) has x as 0, so the y intercept would be 3

Answers: slope = -3/4, y intercept = 3

6 0

3 years ago

Given the replacement set {2, 3, 4, 5}, solve 4x – 3 = 2x + 5.<br> GIVING 20 POINTS !!

Advocard [28]

Answer:

x=4

Step-by-step explanation:

4x - 3 = 2x + 5

4x - 2x = 5 + 3

2x = 8

x = 8/2

x = 4

7 0

3 years ago

When the outliers are removed, how does the mean change? (2 points) dot plot with 1 on 50, 1 on 76, 1 on 78, 2 on 79, 1 on 80, 1

777dan777 [17]

Answer:

Answer: The mean increases by 3

Step-by-step explanation:

The original data set is

{50, 76, 78, 79, 79, 80, 81, 82, 82, 83}

The outlier is 50 because it is not near the group of values from 76 to 83 which is where the main cluster is.

The original mean is M = (50+76+78+79+79+80+81+82+82+83)/10 = 77

If we take out the outlier 50, the new mean is N = (76+78+79+79+80+81+82+82+83)/9 = 80

So in summary so far

old mean = M = 77

new mean = N = 80

The difference in values is N-M = 80-77 = 3

So that's why the mean increases by 3

8 0

3 years ago

A 4-lb. force acting in the direction of (vector) 4,-2 moves an object just over 7ft from point (0,4) to (5,-1). Find the work d

Tcecarenko [31]

To solve this problem, we have to find the net displacement and the net force and the multiply the dot product together and get the work done.

The work done on moving the object is 27ft*lbs

<h3>Work done in moving the object from point A to point B</h3>

To find the work done on this object, let's find the net force on the object.

Data;

force = 4lb
direction = 4, -2
displacement = 7ft
direction = (0, 4) to (5,1)

The unit vector of the force is

$\sqrt{4^2 +(-2)^2} =\sqrt{16 + 4} = \sqrt{20}$

$\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} }$

The net force acting on the object is

$F = 4(\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} })\\F= (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } )$

The displacement on the object is 7ft through (0,4) to (5, -1)

The unit vector on displacement is

$\sqrt{5^2 + (-1-4)^2} = \sqrt{25+25} = \sqrt{50}$

$\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }$

The net displacement will be

$7(\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }) = \frac{35}{\sqrt{50} }, \frac{-35}{50}$

The work done will be F.d

$w = f. d \\$

$w = (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } ) * \frac{35}{\sqrt{50} }, \frac{-35}{50}\\w = 17.71+ 8.854\\w = 26.567 = 27ft*lbs$

The work done on moving the object is 27ft*lbs

Learn more on work done on an object here;

brainly.com/question/26152883

#SPJ1

6 0

2 years ago