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maksim [4K]
3 years ago
15

Write the degree of the polynomial 2y – 13y11​

Mathematics
2 answers:
Sophie [7]3 years ago
4 0

Answer:

Assuming u meant 2y - 13y^(11), the degree is 11

Step-by-step explanation:

lesya [120]3 years ago
4 0

Answer:

Step-by-step explanation:

The highest power is 11 so the degree of polynomial is 11.

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Find the median of each set of data,<br> 12, 8, 6, 4, 10,1<br> 6,3,5, 11, 2,9,5,0<br> 30, 16, 49, 25
Allushta [10]

Answer:

7

Step-by-step explanation:

12, 8, 6, 4, 10, 1, 6, 3, 5, 11, 2, 9, 5, 0, 30, 16, 49, 25

You first need to put it in least to greatest.

> 0, 1, 2, 3, 4, 5, 5, 6, 6, 8, 9, 10, 11, 12, 16, 25, 30, 49 <

Then you go from each side and slowly go towards the middle

Then multiply the two numbers in the middle and divide by two.

5 0
3 years ago
F(x)= x² +5x-2<br> Find the vertex
Setler [38]

Answer:

(-5/2, -33/4)

Step-by-step explanation:

-b/2a

-5/2 = x

f(-5/2) = (-5/2)^2 + 5(-5/2)-2 = -33/4

6 0
3 years ago
Find a parametric representation for the surface. The part of the cylinder y2 + z2 = 121 that lies between the planes x = 0 and
icang [17]

We can borrow from what we know about cylindrical coordinates to set

y(u,v)=11\cos u

z(u,v)=11\sin u

where 0\le u\le2\pi. Then we can let

x(u,v)=v

with 0\le v\le2.

8 0
4 years ago
Read 2 more answers
Hm what is it?????? Answer pls
Annette [7]

Answer:

58

Step-by-step explanation:

set them equal and solve for b

70-2b=28+5b

7b=42

b=6

now plug be back in

28 + 5(6) = 58

5 0
3 years ago
Suppose a sample of 30 employees from the manufacturing industry showed a sample mean of $23.89 per hour. Assume a population st
timama [110]

Answer:

The<em> p</em>-value of the test is 0.1212.

Step-by-step explanation:

A one sample <em>z</em>-test can be performed to determine whether the mean hourly wage differs from the reported mean of $24.57 for the goods-producing industries.

The hypothesis is defined as:

<em>H₀</em>: The mean hourly wage is same as the reported mean of $24.57 for the goods-producing industries, i.e. <em>μ</em> = $24.57.

<em>Hₐ</em>: The mean hourly wage differs from the reported mean of $24.57 for the goods-producing industries, i.e. <em>μ</em> ≠ $24.57.

The information provided is:

\bar x=\$23.89\\n=30\\\sigma=\$2.40

Compute the test statistic as follows:

z=\frac{\bar x-\mu}{\sigma/\sqrt{n}}=\frac{23.89-24.57}{2.40/\sqrt{30}}=-1.55

The test statistic value is, <em>z</em> = -1.55.

Compute the <em>p</em>-value of the test as follows:

p-value=2\times P(Z

*Use a <em>z</em>-table for the probability.

Thus, the<em> p</em>-value of the test is 0.1212.

4 0
4 years ago
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