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3 years ago

Solve the equation.

1 answer:

5 0

If you would like to solve the equation x + 1/6 = 6, you can do this using the following steps:

x + 1/6 = 6 /-1/6
x + 1/6 - 1/6 = 6 - 1/6
x = 6 - 1/6
x = 36/6 - 1/6
x = 35/6
x = 5 5/6

The correct result would be C. x = 5 5/6.

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2 years ago

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3 years ago

Read 2 more answers

What is the average rate of change of f(x) = -x2 + 3x + 6 over the interval –3

Rufina [12.5K]

Answer:

$\frac{\Delta y}{\Delta x} =\frac{f(x_2)-f(x_1)}{x_2-x_1} =\frac{6-(-12)}{3-(-3)} =\frac{18}{6}= 3$

Step-by-step explanation:

To find the average rate of change of a function over a given interval, basically you need to find the slope. The mathematical definition of the slope is very similar to the one we use every day. In mathematics, the slope is the relationship between the vertical and horizontal changes between two points on a surface or a line. In this sense, the slope can be found using the following expression:

$Average\hspace{3}rate\hspace{3}of\hspace{3}change=Slope=\frac{y_2-y_1}{x_2-x_1} =\frac{f(x_2)-f(x_1)}{x_2-x_1}$

So, the average rate of change of:

$f(x)=-x^2+3x+6$

Over the interval $-3$

Is:

$f(x_2)=f(3)=-(3)^2+3(3)+6=-9+9+6=6\\\\f(x_1)=f(-3)=-(-3)^2+3(-3)+6=-9-9+6=-12$

$\frac{\Delta y}{\Delta x} =\frac{f(x_2)-f(x_1)}{x_2-x_1} =\frac{6-(-12)}{3-(-3)} =\frac{18}{6}= 3$

Therefore, the average rate of change of this function over that interval is 3.

3 0

3 years ago

Mr. Tindell divided a 6th grade class Of 80 students an into equal groups the number of students in each group was a prime numbe

zubka84 [21]

Answer:

He made 16 groups which means 5 Students in each group

Step-by-step explanation:

Because 80 divided by 16 is 5 and 5 is a prime number

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3 years ago

How do I solve this?

Olin [163]

Well if it is 1 inch per 100 feet, then we already know that 600 feet is 6 inches on the map. Now the 4 is where it gets trickier. Since it's dividing it by 100 each time, you take 4 and divide it by 100 which is 0.04. Therefore, your answer is 6.04 inches on the map.

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3 years ago