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Rus_ich [418]
2 years ago
13

PLEASE HELP ME WITH THIS

Mathematics
1 answer:
valina [46]2 years ago
5 0

Answer:

there is no correct answer given

Step-by-step explanation:

look at image

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If $1,000 is invested at 16% interest, compounded annually,
Harrizon [31]

Answer:

equation; P=A(1+r/n)^nt

P=principal amount

A=value of investment

r= interest rate in decimals

n=number of times compounded

t=time in years

P=1000(1+0.16/12)^12(5)= $2213.8 rounded

Step-by-step explanation:

8 0
3 years ago
1. FRUITS Find the ratio of bananas to oranges in the graphic at the right. Write the
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Step-by-step explanation:

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7 0
3 years ago
May someone please help me with this :)
CaHeK987 [17]
1. The perimeter = 3.7 + 3.7 + 2.8 + 2.8
= 13
The area = 3.7 * 2.8 = 10.36

2. Perimeter = 11.2
Area = half base times height
2.6 * 1.5 = 3.9 squared
6 0
3 years ago
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(Combining Equations)What is the result of adding these two equations ? 2x + 3y = -5 5x - y = -12
lara [203]

7x +2y =-17 ..... Finally, answer

2x + 3y = -5

+

5x -y = -12

---------------------------

7x +2y = -17

3 0
1 year ago
Find the exact value of cot(15degrees) using half angle formulas?
liubo4ka [24]

Double angle (or half angle, depending how you look at it) identities:

\cos^2\dfrac x2=\dfrac{1+\cos x}2

\sin^2\dfrac x2=\dfrac{1-\cos x}2

\implies\cot^2\dfrac x2=\dfrac{\cos^2\frac x2}{\sin^2\frac x2}=\dfrac{1+\cos x}{1-\cos x}

So we have

\cot^215^\circ=\dfrac{1+\cos30^\circ}{1-\cos30^\circ}=\dfrac{1+\frac{\sqrt3}2}{1-\frac{\sqrt3}2}

\implies\cot^215^\circ=7+4\sqrt3

\implies\cot15^\circ=\sqrt{7+4\sqrt3}=2+\sqrt3

Note that when taking the square root, we should take into account that that could yield two possible solutions, but we know \cos15^\circ>0 and \sin15^\circ>0, so it's also the case that \cot15^\circ>0.

Also, the reason we have equality in the last step can be explained like so:

7+4\sqrt3=4+4\sqrt3+3=4+4\sqrt3+(\sqrt3)^2=(2+\sqrt3)^2

(not unlike the process used to complete the square)

8 0
3 years ago
Read 2 more answers
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