I need help please ....

Mathematics

1 answer:

Kazeer [188]3 years ago

6 0

The correct answer would be A. x=20/3 because it is proportional.

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Shop sells bagles for 5 per dozen how much bagles can you buy for 50

spayn [35]

120 Bagels
Explanation:
if you get 12 bagels for 5 dollars, and your wondering how many you’d get for 50 dollars, 5 times 10 is 50 and 10 times 12 is 120. That doesn’t make the most sense but yes

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4 years ago

An interior designer purchased 4 1/2 yards, 6 2/3 yards and 9 1/4 yards of fabric to make curtains How many yards of fabric did

ArbitrLikvidat [17]

Simply add up all.

4 1/2 + 6 2/3 + 9 1/4

(4 + 6 + 9) + 1/2 + 2/3 + 1/4

19 6/12 + 8/12 + 3/12 = (6+8+3)/12 = 17/12

19 17/12

19 1 5/12

19 + 1 5/12

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3 years ago

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What is the greatest common factor of 10 and 50

brilliants [131]

The greatest number common to 50 and 10 is 10 10 is the answer hope this helps

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3 years ago

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Please help asap!!!!

iren2701 [21]

Answer:

Step-by-step explanation:

yeyeyeye

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3 years ago

A new medical test provides a false positive result for hepatitis 2% of the time that is a perfectly healthy subject being teste

Oxana [17]

Given that X be the number of subjects who test positive for the disease out of the 30 healthy subjects used for the test.

The probability of success, i.e. the probability that a healthy subject tests positive is given as 2% = 0.02

Part A:

The probability that all 30 subjects will appropriately test as not being infected, that is the probability that none of the healthy subjects will test positive is given by:

 $P(X)={ ^nC_xp^x(1-p)^{n-x}} \\ \\ P(0)={ ^{30}C_0(0.02)^0(1-0.02)^{30-0}} \\ \\ =1(1)(0.98)^{30}=0.5455$


Part B:

The mean of a binomial distribution is given by

 $\mu=np \\ \\ =30(0.02) \\ \\ =0.6$

The standard deviation is given by:

 $\sigma=\sqrt{np(1-p)} \\ \\ =\sqrt{30(0.02)(1-0.02)} \\ \\ =\sqrt{30(0.02)(0.98)}=\sqrt{0.588} \\ \\ =0.7668$


Part C:

This test will not be a trusted test in the field of medicine as it has a standard deviation higher than the mean. The testing method will not be consistent in determining the infection of hepatitis.

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3 years ago