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Effectus [21]
3 years ago
10

Construct line AB 11cm and construct a perpendicular P from line AB 6cm​

Mathematics
1 answer:
Arisa [49]3 years ago
8 0
<h3>Step-by-step explanation:</h3>

let us drawn side AB11 cm

again let us drawn p from line AB 6 cm

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The coefficient is -9
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The average yield of the standard variety off soybeans per acre on a farm in a region is 48.8 bushels per acre, with a standard
I am Lyosha [343]

Answer:

z=\frac{53.4-48.8}{\frac{12}{\sqrt{36}}}=2.3  

p_v =P(Z>2.3)=1-P(Z  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significantly higher than 48.8 at 1% of signficance.  

Step-by-step explanation:

1) Data given and notation  

\bar X=53.4 represent the sample mean

\sigma=12 represent the population standard deviation assumed

n=36 sample size  

\mu_o =48.8 represent the value that we want to test  

\alpha=0.01 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

2) State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is higher than 48.8, the system of hypothesis would be:  

Null hypothesis:\mu \leq 48  

Alternative hypothesis:\mu > 48  

Since we assume that know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

3) Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{53.4-48.8}{\frac{12}{\sqrt{36}}}=2.3  

4)P-value  

Since is a right tailed test the p value would be:  

p_v =P(Z>2.3)=1-P(Z  

5) Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significantly higher than 48.8 at 1% of signficance.  

3 0
3 years ago
Hayden is organizing his assets and liabilities in the table below. If his net worth is $17,550, then how much does he have in h
77julia77 [94]

Answer: His checking account balance is $2,800.

Step-by-step explanation: What Hayden is doing is comparing his assets against his liabilities. This will determine his net worth. His assets ideally are those that increase his net worth such as landed properties, etc while his liabilities in the simplest language are those debts he is paying off either right away, or that he must pay off eventually.

In other words, to determine his net worth, Hayden has to add up all his assets and from the total derived, deduct his liabilities.

Consider the calculations below;

NET WORTH: $17,550

Add ASSETS  

                         Automobile               13600  

                         Retirement Account   6700

                         Checking Account      XX

Less LIABILITIES

                          Student Loan            4800

                          Credit card debt          750

Net Worth                                            <u>17550</u>

The above table can be simplified as follows;

Net worth = Assets - Liabilities

17550 = 20300 + XX - 5550

Collecting like terms, you now have;

17550 -20300 +5550 = XX

2800 = XX

The Checking Account represented by XX is now calculated as $2,800

7 0
3 years ago
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