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Cloud [144]
2 years ago
9

A bag contains tiles of different colors. Jackson randomly selects a tile from the bag and returns the tile to the bag after rec

ording the color. Jackson picks a green tile 6 times, a red tile 20 times, a blue tile 7 times, a purple tile 8 times, and a black tile 4 times.

Mathematics
1 answer:
quester [9]2 years ago
3 0

Answer:

2/15

Step-by-step explanation:

The answer choices to this question do not make sense since probability is a measure that is always <= 1.0

Based on the number of times a particular colored tile is drawn we can assume that at the minimum there are 6 green, 20 red, 7 blue, 8 purple and 4 black tiles

Total number of tiles = 6 + 20 + 7 + 8 + 4 = 45

Probability of drawing a green tile = 6/45 = 2/15

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Two plumbers charge different rates for service. The first plumber charges $100 per service call plus $25 per hour of service. T
Bond [772]

Answer: 2

Step-by-step explanation:

6 0
3 years ago
In a process that manufactures bearings, 90% of the bearings meet a thickness specification. A shipment contains 500 bearings. A
Marina86 [1]

Answer:

(a) 0.94

(b) 0.20

(c) 90.53%

Step-by-step explanation:

From a population (Bernoulli population), 90% of the bearings meet a thickness specification, let p_1 be the probability that a bearing meets the specification.

So, p_1=0.9

Sample size, n_1=500, is large.

Let X represent the number of acceptable bearing.

Convert this to a normal distribution,

Mean: \mu_1=n_1p_1=500\times0.9=450

Variance: \sigma_1^2=n_1p_1(1-p_1)=500\times0.9\times0.1=45

\Rightarrow \sigma_1 =\sqrt{45}=6.71

(a) A shipment is acceptable if at least 440 of the 500 bearings meet the specification.

So, X\geq 440.

Here, 440 is included, so, by using the continuity correction, take x=439.5 to compute z score for the normal distribution.

z=\frac{x-\mu}{\sigma}=\frac{339.5-450}{6.71}=-1.56.

So, the probability that a given shipment is acceptable is

P(z\geq-1.56)=\int_{-1.56}^{\infty}\frac{1}{\sqrt{2\pi}}e^{\frac{-z^2}{2}}=0.94062

Hence,  the probability that a given shipment is acceptable is 0.94.

(b) We have the probability of acceptability of one shipment 0.94, which is same for each shipment, so here the number of shipments is a Binomial population.

Denote the probability od acceptance of a shipment by p_2.

p_2=0.94

The total number of shipment, i.e sample size, n_2= 300

Here, the sample size is sufficiently large to approximate it as a normal distribution, for which mean, \mu_2, and variance, \sigma_2^2.

Mean: \mu_2=n_2p_2=300\times0.94=282

Variance: \sigma_2^2=n_2p_2(1-p_2)=300\times0.94(1-0.94)=16.92

\Rightarrow \sigma_2=\sqrt(16.92}=4.11.

In this case, X>285, so, by using the continuity correction, take x=285.5 to compute z score for the normal distribution.

z=\frac{x-\mu}{\sigma}=\frac{285.5-282}{4.11}=0.85.

So, the probability that a given shipment is acceptable is

P(z\geq0.85)=\int_{0.85}^{\infty}\frac{1}{\sqrt{2\pi}}e^{\frac{-z^2}{2}=0.1977

Hence,  the probability that a given shipment is acceptable is 0.20.

(c) For the acceptance of 99% shipment of in the total shipment of 300 (sample size).

The area right to the z-score=0.99

and the area left to the z-score is 1-0.99=0.001.

For this value, the value of z-score is -3.09 (from the z-score table)

Let, \alpha be the required probability of acceptance of one shipment.

So,

-3.09=\frac{285.5-300\alpha}{\sqrt{300 \alpha(1-\alpha)}}

On solving

\alpha= 0.977896

Again, the probability of acceptance of one shipment, \alpha, depends on the probability of meeting the thickness specification of one bearing.

For this case,

The area right to the z-score=0.97790

and the area left to the z-score is 1-0.97790=0.0221.

The value of z-score is -2.01 (from the z-score table)

Let p be the probability that one bearing meets the specification. So

-2.01=\frac{439.5-500  p}{\sqrt{500 p(1-p)}}

On solving

p=0.9053

Hence, 90.53% of the bearings meet a thickness specification so that 99% of the shipments are acceptable.

8 0
3 years ago
Ello ... Random Question
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7 0
3 years ago
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A stack of nickels has a mass of 45g. There are 9 nickels in the stack. What is the mass of one nickel?
melisa1 [442]
The answer is 5g!!!!
8 0
3 years ago
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For f(x) = x3 – x2, which gives an output of 48?<br> O f(-8)<br> O fl-4)<br> O f(4)<br> O f(8)
Misha Larkins [42]

Answer:

f(4)

Step-by-step explanation:

The output is the value of f(x) for a given value of x ( the input )

Substitute the given values of x into f(x) to determine the output, that is

f(- 8) = (- 8)³ - (- 8)² = - 512 - 64 = - 576 ≠ 48

f(- 4) = (- 4)³ - (- 4)² = - 64 - 16 = - 80 ≠ 48

f(4) = 4³ - 4² = 64 - 16 = 48

Thus f(4) gives an output of 48

4 0
2 years ago
Read 2 more answers
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