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vampirchik [111]
2 years ago
14

the Garden Club earn $12 by weeding neighbors Gardens 4X hours a generous donor has agreed to triple their earnings how much did

the garden club earn all right your answer as in expression using parenthesis to show multiplication if needed​
Mathematics
1 answer:
Cerrena [4.2K]2 years ago
8 0

Answer:

The right answer is 15t times 2.

The garden club earns 15 dollars per hour

t is the hours

A generous donor doubles their earnings

Double means times 2

Step-by-step explanation:

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What is the value of ​2×[34−5×(3+1)]​ ?
spayn [35]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{28}}}}}

Step-by-step explanation:

Use BODMAS rule :

Bracket , Of , Division , Multiplication , Addition , Subtraction

\sf{2 \times [ 34 - 5 \times (3 + 1) ] }

Add the numbers : 3 and 1

\dashrightarrow{ \sf{2 \times [ 34 - 5 \times 4 ] }}

Multiply the numbers : 5 and 4

\dashrightarrow{ \sf{2 \times [ 34  - 20 \: ]  }}

Subtract 20 from 34

\dashrightarrow{ \sf{2 \times 14}}

Multiply the numbers : 2 and 14

\dashrightarrow{ \sf{28}}

Hope I helped!

Best regards! :D

4 0
3 years ago
Find the percent of increase from 15 to 20
ANEK [815]
I think it might be 25%
8 0
3 years ago
Read 2 more answers
I need help with 8-11....
MaRussiya [10]
8. Quadrants
9. Proportion
10. Proportionality
11. Dimensional analysis
8 0
3 years ago
Evaluate 2/3+3/4 <br> 1and5/12
chubhunter [2.5K]

2/3 + 3/4 = 8/12 + 9/12 = 17/12 = 1 5/12

1 + 5/12 = 12/12 + 5/12 = 17/12 = 1 5/12

2/3 + 3/4 = 1 + 5/12

6 0
3 years ago
The number of bacteria in a culture is given by the function n(t) =950e^0.45t Where t is measured in hours A) what is the contin
tatiyna

Answer:

a) The continuous rate of growth of this bacterium population is 45%

b) Initial population of culture at t = 0 is 950 bacteria

c) number of bacterial culture contain at t = 5 is 9013 bacteria

Step-by-step explanation:

The number of bacteria in a culture is given by

n(t) = 950e^{0.45t}

a) rate of growth is

Bacteria growth model N(t) = noe^{rt}

Where r is the growth rate

hence r = 0.45

              = 45%

b) Initial population of culture at t = 0

n(0) = 950e^{0.45(0)}

       = 950e^{0}

       = 950 bacteria

c) number of bacterial culture contain at t = 5

n(5) =  950e^{0.45(5)}

      = 950e^{2.25}

      = 9013.35

      = 9013 bacteria

6 0
3 years ago
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