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kondaur [170]
2 years ago
10

How do I solve/ set up equation? Will give brainliest pls help

Mathematics
1 answer:
slamgirl [31]2 years ago
4 0

Answer:

See below ~

Step-by-step explanation:

<u>Finding x</u>

  • 2x - 28 = x/2
  • 3/2x = 28
  • 3x = 56
  • x = 56/3 = 18.66666667

  1. The exact side length of the small square is <u>18.66666667 cm</u> and the exact side length of the big square is <u>37.3333334 cm</u>.
  2. The approximate side length of the small square is <u>18.7 cm</u> and the approximate side length of the big square is <u>37.3 cm</u>.
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Experts/ace helpppp plzzz
Dennis_Churaev [7]

point slope form is y=mx+ b

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b = 6

 so equation is y =1/2x+6

5 0
4 years ago
Find the dimensions of an American football field. The length is 200 ft more than the width, and the perimeter is 1,040 ft. Find
natka813 [3]

Answer:

The width of the football field is 160 feet.

The length of the football field is 360 feet.

Step-by-step explanation:

Let w represent width of the football field.

We have been given that the length is 200 ft more than the width, so the length of the field would be w+200.

We are also told that the perimeter is 1,040 ft. We know that football field is in form of rectangle, so perimeter of field would be 1 times the sum of length and width. We can represent this information in an equation as:

2(w+w+200)=1040

Let us solve for w.

2(2w+200)=1040

4w+400=1040

4w+400-400=1040-400

4w=640

\frac{4w}{4}=\frac{640}{4}

w=160

Therefore, the width of the football field is 160 feet.

Upon substituting w=160 in expression w+200, we will get length of field as:

w+200\Rightarrow 160+200=360

Therefore, the length of the football field is 360 feet.

7 0
3 years ago
PLEASE HELP ME!!!!!!!!!!!
dusya [7]

Answer:

he was being cheated

Step-by-step explanation:

3 0
3 years ago
What is the quadratic formula of 4x2+3x+5=0
maxonik [38]
4x² + 3x + 5 = 0
x = <u>-3 +/- √(3² - 4(4)(5))</u>
                   2(4)
x = <u>-3 +/- √(9 - 80)</u>
                 8
x = <u>-3 +/- √(-71)
</u>                8<u>
</u>x = <u>-3 +/- √(71 × (-1))</u>
                   8
x = <u>-3 +/- √(71) × √(-1)
</u>                    8<u>
</u>x = <u>-3 +/- 8.43i
</u>              8
x = -0.375 +/- 1.05375i
x = -0.375 + 1.05375i      x = -0.375 - 1.05375i
<u />
3 0
3 years ago
A rectangular area adjacent to a river is fenced​ in; no fence is needed on the river side. The enclosed area is 1500 square fee
ZanzabumX [31]

Answer:

a) C(x) = 15000/x + 6x +80

b) Domain of C(x)  { R x>0 }

Step-by-step explanation:

We have:  

Enclosed area = 1500 ft²   = x*y      from which     y  =  1500 / x    (a) where x is perpendicular to the river

Cost = cost of sides of fenced area perpendicular to the river  + cost of side parallel to river + cost of 4 post then

Cost = 10*y + 2*3*x + 4*20 and accoding to (a)  y = 1500/x

Then

C(x)  = 10* ( 1500/x ) + 6*x + 80

C(x) = 15000/x + 6x +80

Domain of C(x)  { R x>0 }

5 0
3 years ago
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