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2 years ago

Comment on the relationship between f and P(E) when N is very large. Why do you think the relationship is this way?

Mathematics

1 answer:

GREYUIT [131]2 years ago

4 0

Answer:

The value of f approaches P(E) when the value of N is very large. Think of the probability of event E as the fraction of times E occurs when the trial is repeated a great number of times.

Step-by-step explanation:

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Please I need help with this question!

likoan [24]

Answer:

I. 60%

II. 75.4 kg

Step-by-step explanation:

We will use the z-scores and the standard normal distribution to answer this questions.

We have a normal distribution with mean 69 kg and variance 25 kg^2 (therefore, standard deviation of 5 kg).

I. What percentage of adult male in Boston weigh more than 72 kg?

We calculate the z-score for 72 kg and then calculate the associated probability:

$z=\dfrac{X-\mu}{\sigma}=\dfrac{72-69}{5}=\dfrac{3}{5}=0.6\\\\\\P(X>72)=P(z>0.6)=0.274$

II. What must an adult male weigh in order to be among the heaviest 10% of the population?

We have to calculate tha z-score that satisfies:

$P(z>z^*)=0.1$

This happens for z=1.28 (see attachment).

Then, we can calculate the weight using this transformation:

$X=\mu+z^*\cdot\sigma=69+1.28\cdot 5=69+6.4=75.4$

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3 years ago

Jill bought 3 cookies and 2 cupcakes for $12.25. Kim bought 5 cookies and 1 cupcake for $14.00.

ziro4ka [17]

Are you asking to find the difference?

7 0

3 years ago

Read 2 more answers

A digital camera memory card is 1/4 full. The card is 2/3 full when 375 more pictures have been taken. How many pictures can the

vlada-n [284]

2/3 is roughly 67%
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3 years ago

Differentiating Functions of Other Bases In Exercise, find the derivative of the function.

aniked [119]

Answer:

$\dfrac{dy}{dx} = \frac{2x-3}{\ln 16(x^2 - 3x)}$

Step-by-step explanation:

We are given the following in the question:

$y = \ln {16}(x^2 - 3x)$

We have to find the derivative of the given expression.

$y = \ln 16(x^2 - 3x)\\\text{Using the log propert}\\\\\log_a b = \dfrac{\log b}{\log a}\\\\dfrac{d(x^n)}{dx} = nx^{n-1}\\\\\dfrac{d(\log x)}{dx} = \dfrac{1}{x}\\\\\text{\bold{Differentiating we get}}\\\\\displaystyle\frac{dy}{dx} = \frac{d(\ln 16(x^2-3x))}{dx}\\\\= \frac{1}{16(x^2-3x)})\frac{d(x^2-3x)}{dx}\\\\=\frac{1}{\log 16(x^2-3x)}(2x - 3)\\\\= \frac{2x-3}{\ln 16(x^2 - 3x)}$

$\dfrac{dy}{dx} = \frac{2x-3}{\ln 16(x^2 - 3x)}$

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4 years ago

Convert the improper fraction to a mixed number. 32/3

AlladinOne [14]

Answer:

32/3 = 10 2/3

Step-by-step explanation:

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3 years ago