2(i).
(3y-20)+(4x-5)+(x+y-10)+(2x+5)=360 (Angles sum of it trapezium)
3y-20+4x-5+x+y-10+2x+5=360
7x+4y=390
(Shown)
2(ii).
(3y-20)+(2x+5)=180 (Interior Angles, Parallel Lines)
2x+3y=195
(Shown)
Hope it helps : )
Answer:
D)
because thats the only answer that would make sence.
Answer:
106.5 square units.
Step-by-step explanation:
See the attached diagram.
The pentagon ABCDE consists of three triangles namely Δ ABC, Δ ACD, and Δ ADE when we join the diagonals AC and AD.
So, Area of Pentagon ABCDE = Area of Δ ABC + Area of Δ ACD + Area of triangle Δ ADE.
⇒ Area of Pentagon ABCDE = (31.8 + 39.2 + 35.5) = 106.5 square units. (Answer)
Answer:
I think this is pythagorean theorem but I'm not sure what I got was 15 for the answer