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2 years ago

Could someone help with a maths question? The attachment has the questions on it.

Mathematics

1 answer:

andre [41]2 years ago

7 0

The days she has recorded: 11 + 10 + 7 + 6 + 3 + 2 = 39
The mode distance (most often): 5 km
Median distance: 6.64 km ~= 6.5 km ~= 7 km by rounding upwards, so 3rd

Cumulative frequency: 11; 21; 28; 34; 37; 39

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PLEASE HELP <br> Show work

dsp73

Answer:

$\tan(24) = \frac{x}{13} \\ 0.445228685308 \times 13 = x \\ x = 5.787972909010 \\ x = 5.788$

$\tan(68) = \frac{27}{x} \\2.475086853416 \times x = 27 \\ x = 27 \div 2.475086853416 \\ x = 10.90870809754 \\ x = 10.909$

$\tan(0) = \frac{5}{12 } \\ \tan(0) = 0.41666663066666 \\ 0 = {76}^{0} 30$

3 0

3 years ago

Hector has $590 in his account. He earned $15 per hour for x hours. Jeremy has $545 in his account. He earned $20 per hour for x

Nutka1998 [239]

Answer:

equation = 590 + 15x = 545 + 20x

No. of hours worked = 9

Step-by-step explanation:

Given that both worked for same number of hours

and

Jeremy worked for for x hours

it meant that Hector also worked for x hours(it is also mentioned same in the problem)

now that we know the number of hours worked in form of x

lets find

total money in their account if they worked for x hours

___________________________________________

For Hector

Money in Hector's account = $590

Earning for Hector in 1 hour = $15

Earning for Hector in x hour = x*Earning for Hector in 1 hour = $15x

Total money in with Hector after x hours of work

= Money in Hector's account + Earning for Hector in x hour = $590 + $15x

Similarly

For Jeremy

Money in Jeremys account = $545

Earning for Jeremy in 1 hour = $20

Earning for Jeremy in x hour = x*Earning for Jeremy in 1 hour = $20x

Total money in with Jeremy after x hours of work

= Money in Jeremy's account + Earning for Jeremy in x hour = $545 + $20x

Given that they same amount of money

thus

$590 + $15x = $545 + $20x

$sign gets cancelled from both sides

590 + 15x = 545 + 20x Thus, we got the required equation

=> 590 - 545 = 20x - 15x

=> 45 = 5x

=> x = 45/5 = 9

Thus, both of them worked for 9 hours

6 0

3 years ago

A sales person makes $200 each week plus an additional $24 per sale. This sales person wants their weekly paycheck to be at leas

Serjik [45]

Answer: a.200 + 24x= 500
b. 12.5 sales but since you can’t make half a sale the answer will be 13

6 0

3 years ago

What is the interquartile range of 4 5 7 9 10 14 16 24

Mama L [17]

2's and 3's of GCF

HOpe iT hElpeED I'M cOOl

7 0

3 years ago

Read 2 more answers

Derivative of<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%7B3x%7D%5E%7B2%7D%20-%202x%20-%201%20%7D%7B%20%7Bx%7D%5E%7B2

Anastaziya [24]

Answer:

$\displaystyle \frac{dy}{dx} = \frac{2x + 2}{x^3}$

Step-by-step explanation:

we would like to figure out the derivative of the following:

$\displaystyle \frac{ { 3x }^{2} - 2x - 1 }{ {x}^{2} }$

to do so, let,

$\displaystyle y = \frac{ { 3x }^{2} - 2x - 1 }{ {x}^{2} }$

By simplifying we acquire:

$\displaystyle y = 3 - \frac{2}{x} - \frac{1}{ {x}^{2} }$

use law of exponent which yields:

$\displaystyle y = 3 - 2 {x}^{ - 1} - { {x}^{ - 2} }$

take derivative in both sides:

$\displaystyle \frac{dy}{dx} = \frac{d}{dx} (3 - 2 {x}^{ - 1} - { {x}^{ - 2} } )$

use sum derivation rule which yields:

$\rm\displaystyle \frac{dy}{dx} = \frac{d}{dx} 3 - \frac{d}{dx} 2 {x}^{ - 1} - \frac{d}{dx} {x}^{ - 2}$

By constant derivation we acquire:

$\rm\displaystyle \frac{dy}{dx} = 0 - \frac{d}{dx} 2 {x}^{ - 1} - \frac{d}{dx} {x}^{ - 2}$

use exponent rule of derivation which yields:

$\rm\displaystyle \frac{dy}{dx} = 0 - ( - 2 {x}^{ - 1 -1} ) - ( - 2 {x}^{ - 2 - 1} )$

simplify exponent:

$\rm\displaystyle \frac{dy}{dx} = 0 - ( - 2 {x}^{ -2} ) - ( - 2 {x}^{ - 3} )$

two negatives make positive so,

$\displaystyle \frac{dy}{dx} = 2 {x}^{ -2} + 2 {x}^{ - 3}$

<h3>further simplification if needed:</h3>

by law of exponent we acquire:

$\displaystyle \frac{dy}{dx} = \frac{2 }{x^2}+ \frac{2}{x^3}$

simplify addition:

$\displaystyle \frac{dy}{dx} = \frac{2x + 2}{x^3}$

and we are done!

5 0

3 years ago