A obtuse isosceles b obtuse scalene c acute isosceles
The result is the perpendicular bisector of AB, perpendicular to the segment AB, and through its midpoint.
<span>if v belongs to V, then we can find scalars a1,a2,...,an, such that
v=a1*v1+a2*v2+...+an*vn,
L1(v)=L1(a1*v1+a2*v2+...+an*vn)
=a1*L1(v1)+a2*L1(v2)+...+an*L1(vn)
=a1*L2(v1)+a2*L2(v2)+...+an*L2(vn)
=L2(a1*v1+a2*v2+...+an*vn)
=L2(v)</span>
Answer:
(0,0), (-1, 1), and (1,-1)
Step-by-step explanation:
If you were to plot all the points they would all end up being on the green line
I hope this helped?
If she got 5/100 wrong she got 95%
95% is the same as 0.95
