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3 years ago

What goes into 8 and 18

Mathematics

2 answers:

Lunna [17]3 years ago

6 0

Step-by-step explanation:

common factor 8 and 18 is 2.

Fittoniya [83]3 years ago

3 0

Answer:

2 goes into 8 and 18

Step-by-step explanation:

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This is due NOW and I’m FREAKING OUT OMG PLEASE HELP......

Wewaii [24]

Answer:

13: Skew

14: Parallel

16: Intersecting

17: Skew

18: No

19: Yes

20: No

21: Yes

Step-by-step explanation:

Skew is when 2 lines dont intersect, nor are parallel (On different planes)

Parallel is when 2 lines are on the same plane, and will never touch

Intersecting is when any set of given points go through each other

8 0

3 years ago

Please help solve for angles Q X and Z

Iteru [2.4K]

Answer:

125

Step-by-step explanation:

Sum of Exterior Angles must add to 360 so

$60 + 70 + 40 + 65 + x = 360$

$235 + x = 360$

$x = 125$

6 0

3 years ago

Which symbol correctly compares these fractions? 13 20 ___ 7 10

fomenos

These are fractions? Like 13/20 and 7/10? Is so the symbol would be 13/20 < 7/10 because 7/10 is a higher fraction than 13/20

7 0

4 years ago

Read 2 more answers

PLZZZZZZ HELP ME I'M GIVING BRAINLIEST AND 14 POINTS

tiny-mole [99]

Answer:

D. 2x - 2 + 3x

Step-by-step explanation:

First, add 2x and 3x. Then you get 5x. Then you get the equivalent expression 5x-2.

5 0

3 years ago

An article presents a study of the failure pressures of roof panels. A sample of 15 panels constructed with 8-inch nail spacing

wariber [46]

Answer:

There is sufficient evidence to conclude that six inches spacing has a higher mean failure pressure than 8 inches

Reject $H_0\ at\ 5%$ level of significance

Step-by-step explanation:

From the question we are told that:

Sample size 1 $n_1=15$

Spacing 1 $s_1=8$

Mean 1 $\=x_1=8.48$

Standard deviation 1 $\sigma_1=0.96 kPa$

Sample size 2 $n_2=16$

Spacing 2 $s_2=6$

Mean 1 $\=x_1=9.93$

Standard deviation 1 $\sigma_1=1.02 kPa$

Generally the hypothesis is mathematically given as

Null $H_0:\mu_1-\mu_2$

Alternative $H_a:\mu_1\mu_2$

Generally the equation for pooled estimate is mathematically given by

$S=\sqrt{\frac{(n_1-1)\sigma_1^2+(n_2-1)\sigma_2^2}{n_1+n_2-2} }$

Therefore

$S=\sqrt{\frac{(15-1)0.96^2+(16-1)1.02^2}{15+15-2} }$

$S=0.9905$

Generally the equation for test statistics is mathematically given by

$t=\frac{\=x_1+\=x_2}{S\sqrt{\frac{1}{n _1}+\frac{1}{n_2}}}$

$t=\frac{\=8.48-9.93}{0.9905\sqrt{\frac{1}{15}+\frac{1}{15}}}$

$t=-4.00091$

Therefore From table

$P value=P(t_{15+15-2}=4.00091)$

$P value=0.00041918$

$P$

Therefore

There is sufficient evidence to conclude that six inches spacing has a higher mean failure pressure than 8 inches

Reject $H_0\ at\ 5%$ level of significance

3 0

3 years ago