Answer:
(x-3), 4 (x - 3)^2 (x + 3) (2 x + 7)
Step-by-step explanation:
Factor all the expressions,
1st expression= 4x^2 - 36=4(x^2-9)=4(x+3)(x-3)
2nd expression=2x^2 - 12x + 18 =2(x^2-6x+9)=2 (x - 3)^2=2(x-3)(x-3)
3rd expression=2x^2 + x - 21=(x - 3) (2 x + 7)
HCF=Commo factor=(x-3)
LCF=Common factor*Remaining factor=4(x+3)(x-3)(x-3) (2 x + 7)=4 (x - 3)^2 (x + 3) (2 x + 7)
The slope would be 1/17 and then you would use that slope and plug it into the y=mx+b and solve for b
10k+(-1)=4k+(-43)
10k-1=4k-43
Subtract 45 from both sides and add 1 to both sides:
6k=-42
Divide by 6 on both sides
k= -7
What exactly are you trying to find?
To fill:
6 hours = 1 tank
1 hour = 1/6 tank
To drain:
It takes 4 times as long, therefore 4 x 6 = 24
24 hours = 1 tank
1hour = 1/24 tank
If both pipes are open
1 hour = 1/6 - 1/24 = 1/8 tank
1/8 tank = 1 hour
8/8 tank = 1 x 8 hour
1full tank = 8 hours
