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Snowcat [4.5K]
2 years ago
12

Jerry was using matrices to solve the system of three equations. He has shown all his steps. Did he make a mistake if so in what

step.

Mathematics
2 answers:
grandymaker [24]2 years ago
5 0

Answer:

Step 3

Step-by-step explanation:

melomori [17]2 years ago
4 0

There are several ways to solve a system of equation; one of these ways is the use of matrix.

<em>Jerry made a mistake at step 2</em>

From the attachment, the step 1 is represented as:

\mathbf{\frac 12R_1 \left[\begin{array}{cccc}1&1&1&0\\5&3&-2&-4\\3&2&1&1\end{array}\right] }

The equation in step 2 is given as:

\mathbf{R_2 = 5R_1 - R_2}

This means that:

We subtract the elements of row 2 from the elements of row 1, multiplied by 5

So, we have:

\mathbf{R_2 = 5\left[\begin{array}{cccc}1&1&1&0\end{array}\right] } - \left[\begin{array}{cccc}5&3&-2&-4\end{array}\right] }

Expand

\mathbf{R_2 = \left[\begin{array}{cccc}5&5&5&0\end{array}\right] } - \left[\begin{array}{cccc}5&3&-2&-4\end{array}\right] }

Subtract corresponding cells

\mathbf{R_2 = \left[\begin{array}{cccc}0&2&7&4\end{array}\right] }

So, the new row 2 elements should be:

\mathbf{ \left[\begin{array}{cccc}0&2&7&4\end{array}\right] }

However, the row 2 elements of Jerry's steps are:

\mathbf{R_2 = \left[\begin{array}{cccc}0&-2&-7&-4\end{array}\right] }

This means that:

Jerry made a mistake; and the mistake is at step 2

Read more about matrix at:

brainly.com/question/21848291

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A sport analyst wants to determine the mean salary of a Baseball player for 2015. He believes an estimate of this average salary
djyliett [7]

Answer:

<em>The large sample size 'n' =  199.6569≅ 200</em>

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

Given Standard deviation of salary for all baseball players for 2015 is about $5,478,384.55

<em>Standard deviation of  of salary for all baseball players for 2015 </em>

<em>   (S.D ) σ =  $5,478,384.55</em>

Given estimate of this average salary for all baseball players for 2015

                          =  $497,000

<em>Given Margin of error of error is  =  $497,000 </em>

<em>Level of significance ∝ = 80% </em>

<em>The critical value Z₀.₂₀ = 1.282  </em>

<u><em>Step(ii):</em></u><em>-</em>

<em>Margin of error of error is  determined by</em>

<em>           </em>M.E = \frac{Z_{0.20} S.D}{\sqrt{n} }<em></em>

<em>          </em>497,000 = \frac{1.282 X 5,478,384.55}{\sqrt{n} }<em></em>

Cross multiplication , we get

 \sqrt{n}  = \frac{1.282 X 5,478,384.55}{497,000 }

On calculation , we get

√n = 14.13

<em>Squaring on both sides, we get</em>

n = 199.6569

<u><em>Conclusion</em></u><em>:-</em>

<em>The large sample size 'n' =  199.6569≅ 200</em>

<em>    </em>

<em></em>

7 0
3 years ago
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