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Stella [2.4K]
3 years ago
8

PLEASE HELP! In a word processing document or on a separate piece of paper, use the guide to construct a two column proof provin

g that triangle RST is congruent to triangle RSQ given that RS ⊥ ST, RS ⊥ SQ, and ∠STR ≅ ∠SQR. Submit the entire proof to your instructor.
Given:
RS ⊥ ST
RS ⊥ SQ
∠STR ≅ ∠SQR

Prove:
△RST ≅ △RSQ

Mathematics
2 answers:
hichkok12 [17]3 years ago
4 0
PLEASE HELP! In a word processing document or on a separate piece of paper, use the guide to construct a two column proof proving that triangle RST is congruent to triangle RSQ given that RS ⊥ ST, RS ⊥ SQ, and ∠STR ≅ ∠SQR. Submit the entire proof to your instructor.

Given:
RS ⊥ ST
RS ⊥ SQ
∠STR ≅ ∠SQR

Prove:
△RST ≅ △RSQ

Kayla Funk2 years ago
0 0

Hiiiiiiiiiiii

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fiasKO [112]
He has 4 loaves of meatloaf
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3 years ago
The focal length F of a lens made by combining two lenses of focal length U and V is given I/F=I/U+I/V
jolli1 [7]

Answer:

a). V=\frac{U.F}{U-F}

b). V = 15 units

Step-by-step explanation:

Focal length F of a lens made by combining two lenses of different focal lengths U and V will be,

\frac{1}{F}=\frac{1}{U}+\frac{1}{V}

A). By solving the given formula,

    \frac{1}{V}=\frac{1}{F}-\frac{1}{U}

    \frac{1}{V}=\frac{U-F}{U.F}

    V=\frac{U.F}{U-F}

B). If F = 6 and U = 10 then we have to find the value of V.

    By substituting the given values in the formula,

    V=\frac{6\times 10}{10-6}

    V=\frac{60}{4}

    V = 15 units

    Therefore, focal length (V) of the lens = 15 units

4 0
3 years ago
A spinner has 3 equal sections labeled X, Y, and Z. Jinghua spins this spinner twice. Which represents all the possible outcomes
gtnhenbr [62]

Answer:

XX, YY, ZZ

Step-by-step explanation:

7 0
3 years ago
PLEASEE HELPPPP!!!!! ASAP SEE ATTACHED!
stiks02 [169]
Short answer: C
Let's start with the pen. 
The length is x
The width is 3 more.= x + 3 
Perimeter of the pen = 2L + 2W
P = 2 L + 2W
P = 2*x + 2(x + 3)
P = 2x + 2x + 6
P = 4x + 6. Leave that for now.

Area of the pen without the doghouse = x(x + 3)
Area of the pen without the doghouse = x^2 + 3x
Area with the doghouse x^2 + 3x - y = 178 (that's his running around space.

Go to the dog house for a Moment
The perimeter of the doghouse and the area are equal and we are told to make them both y.
Area = y
Perimeter = y

Combined facts.
The perimeter of the Pen is three times larger than that of the dog house.
4x + 6 = 3y

The area of the Pen - The area of the doghouse = 178
x^2 + 3x - y = 178

Now what happens is that you have to juggle these two equations so they look like your answer
x^2 + 3x - y = 178
4x + 6 = 3y  Subtract 3y from both sides.
4x - 3y + 6 = 0 Subtract 6 from both sides.
4x - 3y = - 6

Answer C
6 0
3 years ago
What is 15/20 in lowest term
PtichkaEL [24]

Answer:3/4

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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