Please help me!!!!!!!

There are two games involving flipping a coin. In the first game you win a prize if you can throw between 45% and 55% heads. In

Nina [5.8K]

Answer:

d) 300 times for the first game and 30 times for the second

Step-by-step explanation:

We start by noting that the coin is fair and the flip of a coin has a probability of 0.5 of getting heads.

As the coin is flipped more than one time and calculated the proportion, we have to use the <em>sampling distribution of the sampling proportions</em>.

The mean and standard deviation of this sampling distribution is:

$\mu_p=p\\\\ \sigma_p=\sqrt{\dfrac{p(1-p)}{N}}$

We will perform an analyisis for the first game, where we win the game if the proportion is between 45% and 55%.

The probability of getting a proportion within this interval can be calculated as:

$P(0.45$

referring the z values to the z-score of the standard normal distirbution.

We can calculate this values of z as:

$z_H=\dfrac{p_H-\mu_p}{\sigma_p}=\dfrac{(p_H-p)}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_H-p)>0\\\\\\z_L=\dfrac{p_L-\mu_p}{\sigma_p}=\dfrac{p_L-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_L-p)$

If we take into account the z values, we notice that the interval increases with the number of trials, and so does the probability of getting a value within this interval.

With this information, our chances of winning increase with the number of trials. We prefer for this game the option of 300 games.

For the second game, we win if we get a proportion over 80%.

The probability of winning is:

$P(p>0.8)=P(z>z^*)$

The z value is calculated as before:

$z^*=\dfrac{p^*-\mu_p}{\sigma_p}=\dfrac{p^*-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p^*-p)>0$

As (p*-p)=0.8-0.5=0.3>0, the value z* increase with the number of trials (N).

If our chances of winnings depend on P(z>z*), they become lower as z* increases.

Then, we can conclude that our chances of winning decrease with the increase of the number of trials.

We prefer the option of 30 trials for this game.

8 0

2 years ago

Solve w=x/y-x for x.

lesya [120]

Answer:

Rewrite the equation as x+xyz=wx+xyz=w.

x+xyz=wx+xyz=w

Subtract xx from both sides of the equation.

xyz=w−xxyz=w-x

Divide each term by xzxz and simplif

5 0

2 years ago

3. The annual per capita consumption of fresh bananas in the United States can be approximated by a normal distribution, with a

svlad2 [7]

Answer:

The largest annual per capita consumption of bananas in the bottom 5% of consumption is 5.465 lb

Step-by-step explanation:

Given

μ = Mean = 10.4 lb

σ = Standard deviation = 3 lb

Using a confidence level of 90%,

We'll need to first determine the z value that correspond with bottom 5% of consumption of banana

α = 5%

α = 0.05

So,

zα = z(0.05)

z(0.05) = -1.645 ----- From z table

Let x represent the largest annual per capita consumption of bananas

The relationship between x and z is

x = μ + zσ

By substitution;

x = 10.4 + (-1.645) * 3

x = 10.4 - 4.935

x = 5.465

Hence, the largest annual per capita consumption of bananas in the bottom 5% of consumption is 5.465 lb

6 0

3 years ago

This is really difficult for me. If someone could help me I would really appreciate it.

Dmitrij [34]

<span>20, 21, 22, 24, 25, 26, 27, 28, 30. hope that helped</span>

3 0

2 years ago

Read 2 more answers

Which is greater 16.177 or 16.117

Nadusha1986 [10]

The number 16.177 is greater than the number 16.117 because it has a greater value in the hundredths column after the decimal point.

4 0

2 years ago

Read 2 more answers