The function of the area of the square is A(t)=121
Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area
Lets assume the length of side of square is x
11 
⇒x=11t
Area of square=
Area of square=
{as the length of side is 11t}{varies by time}
Area of square=121
Therefore,The function of the area of the square is A(t)=121
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Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area
Lets assume the length of side of square is x
11 
⇒x=11t
Area of square=
Area of square=
{as the length of side is 11t}{varies by time}
Area of square=121
Therefore,The function of the area of the square is A(t)=121
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Answer:
19.5
Step-by-step explanation:
The 43rd term of the sequence is 19.5
5, 20, 80, 320, 1280, 5120, 20480, 81920, 327680, 1310720, 5242880, 20971520
The 12th term would be 20,971,520
Everything is being multiplied by 4 each time
Answer:
y=5x+7
Step-by-step explanation:
parallel lines have the same slope, but different y intercepts
y=5x+7
Answer: 8 oz..
1 pound= 16oz if 8oz=1.59 so add it up 4 times 8+8+8+8= 32 which = 2 pounds total 8=1.59 8+8= 1.59x2=3.18 8+8+8=1.59x3=4.77 8+8+8+8/ 1.59x4= 6.36 so all of them eights will = up to 2 pounds and 8 is obviously less
Step-by-step explanation: