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SCORPION-xisa [38]
3 years ago
15

Please answer me as soon as possible

Mathematics
1 answer:
adell [148]3 years ago
8 0

Answer:????

Step-by-step explanation:

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Martina is currently 10 years older than her cousin Joey. In 3 years she will be 3 times as old as Joey. Use this information to
chubhunter [2.5K]

Answer:

m = j + 10

m + 3 = 3x

Step-by-step explanation:


8 0
3 years ago
3.28×3=9.84 why is this
-Dominant- [34]
3.28·3 = 9.84 is the same as:
3.28+3.28+3.28 = 9.84

Hope this helped! Good luck!
5 0
3 years ago
Suppose the horses in a large stable have a mean weight of 975lbs, and a standard deviation of 52lbs. What is the probability th
Lubov Fominskaja [6]

Answer:

0.8926 = 89.26% probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 975, \sigma = 52, n = 31, s = \frac{52}{\sqrt{31}} = 9.34

What is the probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable?

pvalue of Z when X = 975 + 15 = 990 subtracted by the pvalue of Z when X = 975 - 15 = 960. So

X = 990

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{990 - 975}{9.34}

Z = 1.61

Z = 1.61 has a pvalue of 0.9463

X = 960

Z = \frac{X - \mu}{s}

Z = \frac{960 - 975}{9.34}

Z = -1.61

Z = -1.61 has a pvalue of 0.0537

0.9463 - 0.0537 = 0.8926

0.8926 = 89.26% probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable

7 0
3 years ago
There are 8 members on a board of directors. if they must form a subcommittee of 6 members, how many different subcommittees are
Shtirlitz [24]
1. Given a group of n people. There are C(n, r) ways of forming groups of r out of n.

2. Where C(n, r)=\frac{n!}{r!(n-r)!}

3. For example, given {Andy, John, Julia}. We want to pick 2 people to give a gift: we can pick {(Andy, John), (Andy, Julia), (John, Julia)}, so there are 3 ways. So we can list and count.

4. Or we could do this with the formula C(3, 2)=\frac{3!}{2!(1)!}= \frac{3*2*1}{2*1}=3

5. C(8, 6)=\frac{8!}{2!6!}= \frac{8*7*6!}{2*6!}= \frac{8*7}{2}= 4*7=28

So there are C(8,6)=28 ways of chosing 6 out of 8 people to form the subcommittees. <span />
5 0
3 years ago
2x+4y=1 3x-5y=7<br><br> Find the value of x and y<br><br> Thank you
Rashid [163]

Answer:


2x+4y=13x-5y=7

Too Many Equal Signs



............... V

   2x+4y=13x-5y=7


Program Execution Terminated


 

Tiger was not able to solve for your input:2x+4y=13x-5y=7

Submit your own solution!Step-by-step explanation:


8 0
3 years ago
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