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tekilochka [14]
2 years ago
9

A bag of candy includes pieces with different colors as shown in the table.

Mathematics
1 answer:
zvonat [6]2 years ago
6 0

Part A: About 0.21

      We will put the wanted outcome (yellow pieces of candy) over the total number of possible outcomes (total pieces of candy).

\frac{5}{3+6+5+2+8}

\frac{5}{24}

   About 0.21

Part B: About 50

      First we will do the same as we did with the yellow pieces of candy, wanted outcomes over possible outcomes.

\frac{6}{3+6+5+2+8}

\frac{6}{24}

0.25

      Now, we will multiply the total 200 pieces by 0.25 since 0.25 of them are estimated to be green.

200 * 0.25 = 50

    I estimate about 50 of the pieces to be green.

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