8+8+15+15 I’m not sure if I understand the question correctly but hope I do and i hope this helps
f(2) = 2^2 + 2 + 1
= 4 + 2 + 1
= 7
Answer:
x
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−
1
or
x
>
2
Step-by-step explanation:
Sounds as tho' you have an isosceles triangle (a triangle with 2 equal sides). If this triangle is also a right triangle (with one 90-degree angle), then the side lengths MUST satisfy the Pythagorean Theorem.
Let's see whether they do.
8^2 + 8^2 = 11^2 ???
64 + 64 = 121? NO. This is not a right triangle.
If you really do have 2 sides that are both of length 8, and you really do have a right triangle, then:
8^2 + 8^2 = d^2, where d=hypotenuse. Then 64+64 = d^2, and
d = sqrt(128) = sqrt(8*16) = 4sqrt(8) = 4*2*sqrt(2) = 8sqrt(2) = 11.3.
11 is close to 11.3, but still, this triangle cannot really have 2 sides of length 8 and one side of length 11.
Angle a is a vertical angle with the 30 degree angle above it. We know two of the 3 angles measures in the triangle, 30, 90 and b. All the angles in a triangle = 180 degrees.
30 +90 =120
180 -120 = 60
The measure of b is 60 degrees
angle c and 75 degrees are supplementary angles since a line is 180 degrees.
we can subtract 75 from 180 to find the measure of c.
180-75 =105
Angle a: 30 degrees
Angle b: 60 degrees
Angle c : 105 degrees