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N76 [4]
3 years ago
5

Solve |x+2| >5-(x-1)^2 by graphing

Mathematics
1 answer:
Anna35 [415]3 years ago
7 0

Answer:

x

<

−

1

or

x

>

2

Step-by-step explanation:

You might be interested in
What does x/4=3/2 equal?
MrRissso [65]
x/4 = 3/2
x/2 = 3 (multiply both sides by 2)
x = 6 (multiply both sides by 2)
Therefore 6/4 = 3/2
6 0
3 years ago
Which statement is true of triangles P and Q? Triangle P has side lengths of 6, 8, 10 and angle measures of 53.1 degrees, 90 deg
Wewaii [24]

Answer:

Triangle P and Triangle Q are mathematically similar shapes (?).

Step-by-step explanation:

Hi, so the question asks which statement is true, given the following information, but you haven't written what statements we can choose from.

After reading the information, we can see that Triangle Q is the same shape as Triangle P but just larger.

I'm assuming that one of the statements given is about Triangle P and Triangle Q being mathematically similar shapes?

If you need to show your working out, here it is:

18 ÷ 6 = 3

24 ÷ 8 = 3

30 ÷ 10 = 3

All the angles are the same.

This means that the length scale factor is +3 from Triangle P to Triangle Q, the area scale factor is +9 (because 3 x 3 = 9) from Triangle P to Triangle Q, and that the two shapes are mathematically similar.

*DISCLAIMER* The majority of question askers on Brainly seem to be from the US, and I'm not, so the way I work things out / the mathematical terms I use might be different. Sorry!

Hope this helped anyway!

Bluey :)

3 0
3 years ago
Read 2 more answers
A boat propeller spins 1044 times in 3 MINUTES. Find the rate in revolutions per SECOND.
rodikova [14]

Answer:

The answer is 5.8 times a second

Step-by-step explanation:

Divide 1044 by 180 (The number of seconds in 3 minutes)

8 0
3 years ago
In a group of​ bird-watchers, 3 out of every 5 people have seen a bald eagle. What percent of the​ bird-watchers have not seen a
Salsk061 [2.6K]
40% of the group have not seen a bald eagle.
8 0
3 years ago
Conner and Jana are multiplying (3⁵6⁸)(3⁹6¹⁰).
ad-work [718]
<h3>Conner work is correct. Jana work is wrong</h3>

<em><u>Solution:</u></em>

<em><u>Given that,</u></em>

<em><u>Conner and Jana are multiplying:</u></em>

(3^56^8)(3^96^{10})

Given Conner's work is:

(3^56^8)(3^96^{10}) = 3^{5+9}6^{8+10} = 3^{14}6^{18}

We have to check if this work is correct

Yes, Conner work is correct

From given,

(3^56^8)(3^96^{10})\\\\3^5 \times 6^8 \times 3^9 \times 6^{10}

Use the following law of exponent

a^m \times a^n = a^{m+n}

Therefore,

3^5 \times 6^8 \times 3^9 \times 6^{10} = 3^5 \times 3^9 \times 6^8 \times 6^{10} = 3^{5+9} \times 6^{8+10} = 3^{14} \times 6^{18}

<em><u>Given Jana's work is:</u></em>

(3^56^8)(3^96^{10}) = 3^{5.9}6^{8.10} = 3^{45}6^{80}

This is incorrect

The powers of same base has to be added. But here, powers are multiplied which is wrong

7 0
3 years ago
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