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labwork [276]
3 years ago
14

36​% of college students say they use credit cards because of the rewards program. You randomly select 10 college students and a

sk each to name the reason he or she uses credit cards. Find the probability that the number of college students who say they use credit cards because of the rewards program is​ (a) exactly​ two, (b) more than​ two, and​ (c) between two and five inclusive. If​ convenient, use technology to find the probabilities. ​(a) ​P(2)equals nothing ​(Round to the nearest thousandth as​ needed.)
Mathematics
1 answer:
lana66690 [7]3 years ago
5 0
I did it for you to answer answer please please text please answer question answer answer question please answer please please answer question answer answer please please text please answer answer please me question answer question question because I don’t think I yo ianswer u uI is a good day to go home please please answer answer question answer answer me question answer please answer answer question answer answer me question answer question question because I don’t think know answer question answer please please text me when you
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goldfiish [28.3K]

26-2\left(10-1\right)+\left(3+4\cdot 11\right)

26-(2)(9)+3+(4)(11)

26-18+3+(4)(11)

8+3+(4)(11)

8+3+44

8+47

55

"55 is correct answer".

Hope this helps!

Thanks!

-Charlie

5 0
3 years ago
WILL GIVE BRAINLIEST!!!
grin007 [14]

Answer:

i think the second one

Step-by-step explanation:

i think it would be the smartest thing to pick

7 0
3 years ago
Two problems here I need solved! I need every step, so please have that with your answers!!
Free_Kalibri [48]
QUESTION 1

We want to solve,

\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-6x+8}

We factor the denominator of the fraction on the right hand side to get,

\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-4x - 2x+8}.

This implies
\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x(x-4) - 2(x - 4)}.

\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{(x-4)(x - 2)}

We multiply through by LCM of
(x-4)(x - 2)

(x - 2) + x(x-4) = 2

We expand to get,

x - 2 + {x}^{2} - 4x= 2

We group like terms and equate everything to zero,

{x}^{2} + x - 4x - 2 - 2 = 0

We split the middle term,

{x}^{2} + - 3x - 4 = 0

We factor to get,

{x}^{2} + x - 4x- 4 = 0

x(x + 1) - 4(x + 1) = 0

(x + 1)(x - 4) = 0

x + 1 = 0 \: or \: x - 4 = 0

x = - 1 \: or \: x = 4

But
x = 4
is not in the domain of the given equation.

It is an extraneous solution.

\therefore \: x = - 1
is the only solution.

QUESTION 2

\sqrt{x+11} -x=-1

We add x to both sides,

\sqrt{x+11} =x-1

We square both sides,

x + 11 = (x - 1)^{2}

We expand to get,

x + 11 = {x}^{2} - 2x + 1

This implies,

{x}^{2} - 3x - 10 = 0

We solve this quadratic equation by factorization,

{x}^{2} - 5x + 2x - 10 = 0

x(x - 5) + 2(x - 5) = 0

(x + 2)(x - 5) = 0

x + 2 = 0 \: or \: x - 5 = 0

x = - 2 \: or \: x = 5

But
x = - 2
is an extraneous solution

\therefore \: x = 5
7 0
3 years ago
Rachel, Adam, Michelle, Hannah, and James are going to the movies. They have $65 to spend on tickets and snacks. Each movie tick
alex41 [277]

Steps to solve:

47.5 + 4.5x ≤ 65

~Subtract 47.5 to both sides

4.5x ≤ 17.5

~Divide 4.5 to both sides

x ≤ 3.8888888889...

So, yes, the friends will have to share snacks.

Best of Luck!

3 0
3 years ago
Read 2 more answers
A building was planned to be built in an area north of 8th Street and east of Main Street, as shown below.
dalvyx [7]

Answer:

D

Step-by-step explanation:

4 0
3 years ago
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