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labwork [276]
3 years ago
14

36​% of college students say they use credit cards because of the rewards program. You randomly select 10 college students and a

sk each to name the reason he or she uses credit cards. Find the probability that the number of college students who say they use credit cards because of the rewards program is​ (a) exactly​ two, (b) more than​ two, and​ (c) between two and five inclusive. If​ convenient, use technology to find the probabilities. ​(a) ​P(2)equals nothing ​(Round to the nearest thousandth as​ needed.)
Mathematics
1 answer:
lana66690 [7]3 years ago
5 0
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Help me pls I don’t know how to do this I’ll give brainliest pls help
Natalka [10]

Answer:

3/2

Step-by-step explanation:

First, you find the mean (((4 + 5 + 6 + 1)/4) = 4)

Find the absolute difference between each data value and the mean: 0, 1, 2, 3

Add the differences (in the previous step) and divide by number of terms: (0+1+2+3)/4 = 6/4 = 3/2

3 0
2 years ago
5x + 7y = -29, y = x + 1
Afina-wow [57]

Answer:d

Step-by-step explanation:

6 0
2 years ago
What’s standard form of y=6x-4
Natalija [7]

Answer: probably y= -24


Step-by-step explanation:


5 0
3 years ago
What are the dimensions of a rectangular box with a volume of 50b 3 + 75b2 - 2b - 3?
Inessa [10]

Answer:

\large\boxed{(2b+3)\times(5b-1)\times(5b+1)}

Step-by-step explanation:

The formula of a volume of a rectangular box:

V=lwh

<em>l</em><em> - lenght</em>

<em>w</em><em> - width</em>

<em>h</em><em> - height</em>

V=50b^3+75b^2-2b-3=25b^2(2b+3)-1(2b+3)\\\\=(2b+3)(25b^2-1)=(2b+3)(5^2b^2-1^2)\\\\=(2b+3)\bigg((5b)^2-1^2\bigg)\qquad\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=(2b+3)(5b-1)(5b+1)

Therefore the dinemsions of thisp prism are:

(2b+3)\times(5b-1)\times(5b+1)

5 0
2 years ago
Read 2 more answers
Plsssssss help<br>got 20 mins​<br>the question is: The sin of angle DCB is
Elena L [17]

Answer:

i. <DCB = 53.13^{o}

ii. Sin of <DCB = 0.8

Step-by-step explanation:

Let <DCB be represented by θ, so that;

Sin θ = \frac{opposite}{hypotenuse}

Thus from the given diagram, we have;

Sin θ = \frac{4}{5}

        = 0.8

This implies that,

θ = Sin^{-1} 0.8

   = 53.1301

θ = 53.13^{o}

Therefore, <DCB = 53.13^{o}.

So that,

Sin of <DCB = Sin 53.13^{o}

                    = 0.8

Sin of <DCB = 0.8

5 0
2 years ago
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